If the patient is given 150 mL/h of IV saline for 1.5 h 1.97 g NaCl she receive.
<h3>What is Molarity ?</h3>
Molarity (M) is defined as the number of moles of solute dissolved in 1L of solution. Molarity is also known as Molar Concentration. The S.I unit of Molarity is molar (M) or mol/L.
It is expressed as:
Molarity (M) =
Molarity × Volume of solution = Number of moles
As we know that
Number of moles =
So,
Molarity × Volume of solution =
Molarity × Volume of solution × Molar Mass = Mass
Volume =
= 225 mL
Mass of NaCl = Molarity × Volume of solution × Molar Mass
= (0.15 mol/L NaCl) × (58.44 g/mol NaCl) × (225 ml × 0.001)
= 1.97 g NaCl
Thus from the above conclusion we can say that If the patient is given 150 mL/h of IV saline for 1.5 h 1.97 g NaCl she receive.
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Answer:
1.54 ml
2. 54 g
3. -43.7 °C
4. 97 g
5. 17.74 kJ
Explanation:
1. Volume of water that only came from the melted ice is;
Volume of water plus melted ice-volume of warm water
151 ml - 97 ml = 54 ml
2.Mass of water that came from the melted ice.
Mass=density of water * volume of water from melted ice
M=1 g/ml * 54 ml = 54 g
3. The change in temperature of warm water will be;
Lowest temperature of ice-water mixture-Temperature of warm water
ΔT=0.9-44.6 = -43.7
4. Mass of warm water will be;
Mass of warm water= density of water*volume of warm water
M=1g/ml * 97 = 97 g =0.097 kg
5.
Energy released by warm water as it cools
Q=mcΔT
Given , mass of warm water=m=97
c=4.184 j/g*°C = 4184 J/(kg.C)
Δ= - 43.7
Q=0.097*4184*43.7 =17735.56 J
17735.56/1000 =17.74 kJ
Phosphates and deoxyribose
I believe that option C should be correct
Answer:
a) Pex = 15 bar
b) work = 3000 J
Explanation:
<u>Step 1: </u>Data given
Volume of the gas = 2.5 dm³
Pressure of the gas = 3.00 bar
The gas is compressed at a constant pressure pex , so that the final volume is 0.5 dm³
The final temperature is the same as in the beginning.
<u>Step 2:</u> Calculate Pex
If the gas is compressed isothermally ( =constant temperature), then via the ideal gas law we can write:
P2 =Pex = (P1*V1)/V2
Pex = (3 * 2.5)/0.5
Pex = 15 bar
<u>Step 3:</u> Calculate the work
If Pex is constant, then is:
w = −
∫Pex *dV = -Pex *ΔV = -15 *(0.5-2.5)dm³ = 30dm³ bar
30dm³ bar * 10^5 Pa
/bar * 0.1³ m³/dm³ =3000 kg*m²/s² = 3000 J