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Marina CMI [18]
3 years ago
8

a 45 gram marble is dropped into a graduated cylinder with 30ml of water. The water level increases to 45.0 ml. What is the dens

ity of the marble?
Chemistry
1 answer:
Lady bird [3.3K]3 years ago
5 0

Answer:

<h2>3 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}\\

From the question we have

volume = final volume of water - initial volume of water

volume = 45 - 30 = 15 ml

We have

density =  \frac{45}{15}  = 3 \\

We have the final answer as

<h3>3 g/mL</h3>

Hope this helps you

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<h3>Answer:</h3>

1.2 × 10⁻⁸ mol Pb

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
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<u>Stoichiometry</u>

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<u>Step 1: Define</u>

[Given] 7.2 × 10¹⁵ atoms Pb

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 7.2 \cdot 10^{15} \ atoms \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ atoms \ Pb})
  2. [DA] Multiply/Divide [Cancel out units]:                                                            \displaystyle 1.19562 \cdot 10^{-8} \ mol \ Pb

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1.19562 × 10⁻⁸ mol Pb ≈ 1.2 × 10⁻⁸ mol Pb

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