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3 years ago

What can be concluded about the purpose many robots will have in the future

Chemistry

2 answers:

LekaFEV [45]3 years ago

8 0

They can help humans out and program some stuff out

GenaCL600 [577]3 years ago

3 0

Answer:

Robots will be created to allow scientists to use computer programs.

Explanation:

There are some other answers, but this one is more sufficient. :)

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galina1969 [7]

There will be 18 oxygen Atoms

3 0

3 years ago

What type of changes indicate a physical change?

Illusion [34]

vaporisation, Freezing, Condensation

6 0

4 years ago

The flavor of anise is due to anethole, a compound with the molecular forumal C10H12O. Combustion of one mole of anethole produc

AfilCa [17]

Answer:

Change in temperature of calorimeter is $4.52^{0}\textrm{C}$

Explanation:

Molar mass of anethole = 148.2 g/mol

So, 0.950 g of anethole = $\frac{0.950}{148.2}moles$ of anethole = 0.00641 moles of anethole

1 mol of anethole releases 5541 kJ of heat upon combustion

So, 0.00641 moles of anethole release $(5541\times 0.00641)kJ$ of heat or 35.52 kJ of heat

7.854 kJ of heat increases $1^{0}\textrm{C}$ temperature of calorimeter.

So, 35.52 kJ of heat increases $(\frac{1}{7.854}\times 35.52)^{0}\textrm{C}$ or $4.52^{0}\textrm{C}$ temperature of calorimeter

So, change in temperature of calorimeter is $4.52^{0}\textrm{C}$

7 0

3 years ago

I know that the answer is C. 8, but can you explain step by step how to get that answer?

Leya [2.2K]

Answer:

Explanation:

Oxidation:

$Fe^{2+} -->Fe^{3+}+e^{-}$

Reduction:

$Cr_{2}O_{7}^{2-}+6e^{-} -->2Cr^{3+}$

We have to equalise the number of moles of electrons gained and lost in a redox reaction in order to get a balanced reaction.

Hence we have to multiply the oxidation reaction throughout by 6.

and adding the two half-reactions we obtain:

$6Fe^{2+}+Cr_{2}O_{7}^{2-} -->6Fe^{3+}+2Cr^{3+}$

Still the total charge and number of oxygen is not balanced.

Since the reaction takes place in acidic conditions, we will add required number of H+ to the appropriate side to balance the charge and add half the amount of H2O to balance the hydrogen atoms.

We add 14 H+ on LHS and 7H2O on RHS to obtain:

$6Fe^{2+}+Cr_{2}O_{7}^{2-}+14H^{+} -->6Fe^{3+}+2Cr^{3+}+7H_{2}O$

Sum of coefficients of product cations = 6+2 = 8

4 0

3 years ago

100 POINTS & BRAINLIEST !!!! PLEASE HELP

il63 [147K]

Carbon, C, P Block, 2, 6, 12.0107u. 6 protons, 6 electrons, 6 neutrons

Helium, He, S Block, 1, 2, 4.0026u, 2 protons, 2 electrons, 2 neutrons

Germanium, Ge, P Block, 4, 32, 72.64u, 32 protons, 32 electrons, 41 neutrons

Oxygen, O, P Block, 2, 8, 16u, 8 protons, 8 electrons, 8 neutrons

Scandium, Sc, D Block, 4, 21, 44.9559u, 21 protons, 21 electrons, 24 neutrons

Tellurium, Te, P Block, 5, 52, 127.60u, 52 protons, 52 electrons, 76 neutrons

Hydrogen, H, S Block, 1, 1, 1.008u, 1 proton, 1 electron, 0 neutrons

Iron, Fe, D Block, 4, 26, 55.845u, 26 protons, 26 electrons, 30 neutrons

Beryllium, Be, S Block, 2, 4, 9.012u, 4 protons, 4 electrons, 5 neutrons

Vanadium, V, D Block, 4, 23, 50.942u, 23 protons, 23 electrons, 28 neutrons

Silver, Ag, D Block, 5, 47, 108u, 47 protons, 47 electrons, 61 neutrons

Gallium, Ga, P Block, 4, 31, 69.723u, 31 protons, 31 electrons, 39 neutrons

Bromine, Br, P Block, 4, 35, 79.904u, 35 protons, 35 electrons, 45 neutrons

Fluorine, F, P Block, 2, 9, 18.998u, 9 protons, 9 electrons, 10 neutrons

Manganese, Mn, D Block, 4, 25, 54.938u, 25 protons, 25 electrons, 30 neutrons

Strontium, Sr, S Block, 5, 38, 87.62u, 38 protons, 38 electrons, 50 neutrons

Francium, Fr, S Block, 7, 87, 223u, 87 protons, 87 electrons, 136 neutrons

8 0

3 years ago

Read 2 more answers