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sesenic [268]
3 years ago
9

Please help me with this. (: I'd appreciate it.

Chemistry
1 answer:
Soloha48 [4]3 years ago
4 0

Answer:

The answer to your question is:  ΔH = -283 kJ/mol, first option

Explanation:

Reaction

                CO  +  O₂     ⇒     CO₂

ΔH = ∑H products - ∑H products

ΔH = -393.5 - (-110.5 + 0)

ΔH = -393.5 + 110.5

ΔH = -283 kJ/mol

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At 85°C, the vapor pressure of A is 566 torr and that of B is 250 torr. Calculate the composition of a mixture of A and B that b
Phantasy [73]

Answer:

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Explanation:

If the ideal solution model is assumed, and the vapor phase is modeled as an ideal gas, the vapor pressure of a binary mixture with x_{A} and x_{B} molar fractions can be calculated as:

P_{vap}=x_{A}P_{A}+x_{B}P_{B}

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0.60*760=P_{vap}=x_{A}P_{A}+x_{B}P_{B}\\456=x_{A}P_{A}+(1-x_{A})P_{B}\\456=x_{A}*(P_{A}-P_{B})+P_{B}\\\frac{456-P_{B}}{P_{A}-P_{B}}=x_{A}\\\\\frac{456-250}{566-250}=x_{A}=0.652

With the same assumptions, the vapor mixture may obey to the equation:

x_{A}P_{A}=y_{A}P, where P is the total pressure and y is the fraction in the vapor phase, so:

y_{A} =\frac{x_{A}P_{A}}{P}=\frac{0.652*566}{456} =0.809=80.9 %

The fractions of B can be calculated according to the fact that the sum of the molar fractions is equal to 1.

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