Answer:
Only
gives spontaneous reaction.
Explanation:
A redox reaction will be spontaneous if standard reduction potential (
) of the reaction is positive. Because it leads to negative standard gibbs free energy change (
), which is a thermodynamic condition for spontaneity of a reaction.

Where
and
represents standard reduction potential of reduction half cell and standard reduction potential of oxidation half cell.
(1) Oxidation:
; 
Reduction:
; 
So, 
Hence this pair will give spontaneous reaction.
(2) Similarly as above, 
Hence this pair will give non-spontaneous reaction.
(3) Similarly as above, 
Hence this pair will give non-spontaneous reaction.
(4) Similarly as above, 
Hence this pair will give non-spontaneous reaction.
Answer:
According to Le-chatelier principle, equilibrium will shift towards left to minimize concentration of
and keep same equilibrium constant
Explanation:
In this buffer following equilibrium exists -

So,
is involved in the above equilibrium.
When a strong base is added to this buffer, then concentration of
increases. Hence, according to Le-chatelier principle, above equilibrium will shift towards left to minimize concentration of
and keep same equilibrium constant.
Therefore excess amount of
combines with
to produce ammonia and water. So, effect of addition of strong base on pH of buffer gets minimized.
Answer:
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Answer : The molar concentration of sucrose in the tea is, 0.0549 M
Explanation : Given,
Mass of sucrose = 3.765 g
Volume of solution = 0.200 L
Molar mass of sucrose = 342.3 g/mole
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :

Now put all the given values in this formula, we get:

Therefore, the molar concentration of sucrose in the tea is, 0.0549 M
When in water, MgCl2 dissociates into magnesium ions and Cl- ions and NaOH into Na and OH ions. The equation is as follows:
MgCl2 = Mg2+ + 2Cl-
NaOH = Na+ + OH-
The initial concentrations are as follows:
[Mg2+] = .220(<span> 2.47x10^-4) / .220+.180 = 1.36x10^-4 M Mg2+
</span>[OH-] = .180 (3.52x10^-4) / .220+.180 = 1.58x10^-4 M OH-