What was Ernest Rutherford's experiment?

How many grams of iron are needed to produce 3 g of iron(III) chloride?

Ivanshal [37]

Answer:

5 its just what i do

Explanation:

4 0

2 years ago

Iron(III) oxide and hydrogen react to form iron and water, like this: Fe_2O_3(s) + 3H_2(g) rightarrow 2Fe(s) + 3H_2O(g) At a cer

Sergeeva-Olga [200]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The equilibrium constant is $K_c= 2.8*10^{-4}$

Explanation:

From the question we are told that

The chemical reaction equation is

$Fe_{2} O_{3}_{(s)} + 3H_{2}_{(g)} -----> 2Fe_{(s)} + 3H_{2} O_{(g)}$

The voume of the misture is $V_m = 5.4L$

The molar mass of $Fe_{2} O_{3}_{(s)}$ is a constant with value of $M_{Fe_{2} O_{3}_{(s)} } = 160g/mol$

The molar mass of $H_{2}_{(g)}$ is a constant with value of $H_2 = 2g/mol$

The molar mass of $H_{2}O$ is a constant with value of $H_2O = 18g/mol$

Generally the number of moles is mathematically given as

$No \ of \ moles \ = \frac{mass}{molar\ mass}$

For $Fe_{2} O_{3}_{(s)}$

$No \ of\ moles = \frac{3.54}{160}$

$= 0.022125 \ mols$

For $H_{2}$

$No \ of\ moles = \frac{3.63}{2}$

$= 1.815 \ mols$

For $H_{2}O$

$No \ of\ moles = \frac{2.13}{18}$

$= 0.12 \ mols$

Generally the concentration of a compound is mathematicallyrepresented as

$Concentration = \frac{No \ of \ moles }{Volume }$

For $Fe_{2} O_{3}_{(s)}$

$Concentration[Fe_2 O_3] = \frac{0.222125}{5.4}$

$= 4.10*10^{-3}M$

For $H_{2}$

$Concentration[H_2] = \frac{1.815}{5.4}$

$= 0.336M$

For $H_{2}O$

$Concentration [H_2O] = \frac{0.12}{5.4}$

$= 0.022M$

The equilibrium constant is mathematically represented as

$K_c = \frac{[concentration \ of \ product]}{[concentration \ of \ reactant ]}$

Considering $H_2O \ for \ product$

And $H_2 \ for \ reactant$

At equilibrium the

$K_c = \frac{0.022}{0.336}$

$K_c= 2.8*10^{-4}$

3 0

2 years ago

If an element A has 3 shells and has 3 valence electrons, write formulas for the following:

Ilya [14]

Electron configuration

an element A has 3 shells and has 3 valence electrons

so electron configuration of A: 1s², 2s², 2p⁶, 3s², 3p¹

will tend to lose 3 electron to form a cation: A³⁺

a. Nitrate of A

A(NO₃)₃

b. Chloride of A

ACl₃

c. Oxide of A

A₂O₃

6 0

2 years ago

An aqueous solution of methanol (MM = 32.04 g/mol) has a molality of 8.83 m and a density of 1.15 g/mL. What is the molarity of

hodyreva [135]

We have that the the molarity of methanol in the solution is mathematically given as

Morality=7.91mol/l

<h3>Chemical Reaction</h3>

Question Parameters:

An <u>aqueous </u><em>solution </em>of methanol (MM = 32.04 g/mol)

A molality of 8.83 m and a density of 1.15 g/mL.

Generally the equation for the is mathematically given as

$Morality=\frac{moles of solute }{mass of the solvent}$

where

Mass of solution=(100+282.2)

Mass of solution=1289.9

Volume=1289.9/1.15

Volume=1.115L

Therefore

$Morality=\frac{moles of solute }{mass of the solvent}$

Morality=8.83/1.115

Morality=7.91mol/l

For more information on Chemical Reactionvisit

brainly.com/question/11231920

7 0

2 years ago

If I had a mixture of salt, sand, and iron filings I could separate the mixture by …

liubo4ka [24]

Okay to separate this mixture you will have to first use a magnet because the magnet will attract the iron filings out of the sand then you will remain with the sand and salt.

Next step is to add water to the sand and salt mixture the salt will dissolve in the water and the sand will not forming a heterogeneous mixture.Then using the method of filtration you can separate the sand from the salt solution leaving the salt solution

To separate the salt from the water use the method of evaporation this will enable you to get back the salt

In the end you should beable to have the sand,salt and iron filings separate.

Hope this was helpful to you.

Happy New Years !!! May your year be prosperous

3 0

2 years ago

What was Ernest Rutherford's experiment?​

What was Ernest Rutherford's experiment?