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elixir [45]
3 years ago
11

Polycarbonate plastic has density of 1.2g/cm cube

Chemistry
1 answer:
Nastasia [14]3 years ago
5 0

Answer:I did not understand the question nicely by from whatever i understand the answer is yes

Explanation:

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Four research teams measured the length of a rare whale, and what each team wrote in its team notebook is shown in the table bel
vovikov84 [41]

Answer:

Explanation:

Precision relates to instruments of measurement or scale . A scale measuring upto cm is less precise than an instrument measuring upto mm .

Here the first measurement appears to have been taken with an instrument measuring up to metre and the second measurement appears to have been taken with an instrument measuring up to decimeter . So second measurement is most precise .

Third measurement is closest to the actual measurement that is 45.0 m , so it is most accurate measurement .

6 0
3 years ago
A system is composed of 7.14 grams of Ne gas at 298 K and 1 atm. When 2025 joules of heat are added to the system at constant pr
dlinn [17]

Answer:

(a) 1 atm, 8.72 L and 298 K respectively.

(b) 1 atm, 16.72 L and 573.35 K respectively.

(c) \Delta U=1215J

Explanation:

Hello,

(a) In this case, considering that neon could be considered as an ideal gas, we can compute its volume as follows:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{7.14g*\frac{1mol}{20g}0.082\frac{atm*L}{mol*K}*298K}{1atm}\\  \\V=8.72L

Thus, initial conditions of pressure volume and temperature are 1 atm, 8.72 L and 298 K respectively.

(b) Since the process was carried out at constant pressure, the work is defined as:

W=P(V_2-V_1)

Thus, the final volume is:

V_2=\frac{W}{P} +V_1=\frac{810Pa*m^3}{1atm*\frac{101325Pa}{1atm} } *\frac{1000L}{1m^3}+8.72L\\ \\V_2=16.72L

And the final temperature is computed by considering the pressure-constant specific heat of neon (1.03 J/g*K) and the added heat:

Q=mCp(T_2-T_1)\\\\T_2=\frac{Q}{mCp}+T_1 =\frac{2025J}{7.14g*1.03J/(g*K)}+298K\\ \\T_2=573.35K

Therefore, final volume is 16.72 L, final pressure is also 1 atm and final temperature is 573.35 K for this expansion process.

(c) Finally, the change in the internal energy is computed via the first law of thermodynamics:

Q-W=\Delta U\\\\\Delta U=2025J-810J\\\\\Delta U=1215J

Best regards.

8 0
4 years ago
Which of these is something whose construction MOST LIKELY would be determined by the government? A) An airport B) A golf club C
Amiraneli [1.4K]

Answer:

I would say an airport

Explanation:

why because it is ran by the government

8 0
3 years ago
Read 2 more answers
How many kilometers can the car travel on the amount of gasoline that would fit in a soda can? The volume of a soda can is 355 m
g100num [7]
I'll assume that the car is a Honda Insight with <span>EPA gas mileage rating of 57mi/gal in the city.

First, we will convert all units into Km and mL:
1 mile = </span><span>1.609344 Km
</span><span>1gal = 3785.411 mL
</span>
Then, we will calculate the distance the car can move by multiplying the mileage rating and the the volume available as follows (note that I will be converting units in the same step):
distance = <span>(57mi/gal) x (1.609344 km/1mi) x (1gal/3785.411mL) x 355mL 
               = 8.6027 Km</span>
4 0
4 years ago
Read 2 more answers
The breakdown of dopamine is catalyzed by the enzyme monoamine oxidase (MAO). What is the final concentration of product if the
kotegsom [21]

Answer:

final concentration: Ca = 0.014 M

Explanation:

Velocity of reaction:

  • ra = K(Ca)∧α = δCa/δt

∴ α: order of reaction, assuming α = 1

∴ K = 0.249 s-1.......rate constant

∴ Cao = 0.050 M......initial concentration

∴ t = 5 s.......reaction time

⇒ δCa/δt = K*Ca

⇒ ∫δCa/Ca = K*∫δt

⇒ Ln(Cao/Ca) = K*t = (0.249s-1)(5 s) = 1.245

⇒ Cao/Ca = 3.473

⇒ Ca = 0.050/3.473

⇒ Ca = 0.014 M

3 0
3 years ago
Read 2 more answers
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