Answer:
The answer to your question is 55.224 g of NiCl₂
Explanation:
I will solve it and then I compare the results.
Data
Volume = 0.8 l
Molarity = 0.531
substance = NiCl₂
Process
1.- Calculate the molar mass of NiCl₂
NiCl₂ = 59 + (35.5 x 2)
= 130 g
2.- Calculate the number of moles
Molarity = moles / volume
-Solve for moles
moles = Molarity x volume
-Substitution
moles = 0.531 x 0.8
-Result
moles = 0.4248
3.- Convert the moles to mass
130 g -------------------- 1 mol of NiCl₂
x -------------------- 0.4248 moles
x = (0.4248 x 130) / 1
-Simplifying
x = 55.224 / 1
-Result
x = 55.224 g of NiCl₂
4.- We need 55.224 g of NiCl₂ to prepare 0.8l of a solution 0.531 M.
You have similar results, just our molar mass is different.
Answer:
σ -> 2sp²
π -> 2p
Explanation:
The carbon has valence shell 2s 2p, and, both of them make 3 σ bonds and 1 π bond. The π bond only occurs in multiple bonds.
The σ bonds happen at the hybrids orbitals, which are orbitals formed by the association of the pure orbitals (s, p, d, f). The hybridization occurs to make possible to the atom to do the bonds because the electrons need to be isolated in it.
On the other hand, the π bonds only occur at pure orbitals. The subshell s only has 1 orbital, and the subshell p has 3 orbitals. So, because there are 3 σ bonds, it's necessary 3 hybrids orbitals (1 of s + 2 of p).
The σ bonds happen at the orbital 2sp² and the π bond at the 2p pure orbital.
Explanation:
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