Let's eliminate these one by one.
The first pair would not be the same, as X would most likely be in group IA, and Y would be in group VIIA, because of their tendency to gain and lose electrons.
The second pair would also violate the same rule, but X would most likely be in group IIA, and Y would most likely be in group VIA.
The third pair would not be the same, as X is most likely in group VIIA, and since Y has eight valence electrons, it is most likely a noble gas.
The final pair has X with atomic number 15, making it phosphorous. Phosphorous wants to gain 3 electrons to have a full octet of 8 outer "valence" electrons, and Y would also like to gain 3 electrons. This means it is possible that the final pair would be in the same group.
Answer:
c. 0.1 M Ga₂(SO₄)₃
Explanation:
The boiling point increasing of a solvent due the addition of a solute follows the formula:
ΔT = K*m*i
<em>Where K is boiling point increasing constant (Depends of the solute), m is molality = molarity when solvent is water, and i is Van't Hoff factor.</em>
<em />
That means the option with the higher m*i will be the solution with the highest boiling point:
a. NaCl has i = 2 (NaCl dissociates in Na⁺ and Cl⁻ ions).
m* i = 0.20*2 = 0.4
b. CaCl₂; i = 3. 3 ions.
m*i= 0.10M * 3 = 0.3
c. Ga₂(SO₄)₃ dissolves in 5 ions. i = 5
m*i = 0.10M*55 = 0.5
d. C₆H₁₂O₆ has i = 1:
m*i = 0.2M*1 = 0.2
The solution with highest boiling point is:
<h3>
c. 0.1 M Ga₂(SO₄)₃</h3>
Answer:
The potential energy decreases whereas the kinetic energy increases.
Answer:
False
Explanation:
Some substances don't have to be
Answer:
⇒ We have Na2O + H2O --> NaOH. We have 2 sodiums and 2 oxygens and 2 hydrogens on the left side, but only one of each on the right side.
Sodium Oxide + Water → Sodium Hydroxide
⇒ Na2O + H2O → 2NaOH .
Sodium oxide is used in ceramics and glasses. Sodium oxide reacts exothermically with cold water to produce sodium hydroxide solution.
