Step one calculate the moles of each element
that is moles= % composition/molar mass
molar mass of Ca = 40g/mol, S= 32 g/mol , O= 16 g/mol
moles of Ca = 29.4 /40g/mol=0.735 moles, S= 23.5/32 =0.734 moles, O= 47.1/16= 2.94 moles
calculate the mole ratio by dividing each mole with smallest mole that is 0.734
Ca= 0.735/0.734= 1, S= 0.734/0.734 =1, O = 2.94/ 0.734= 4
therefore the emipical formula = CaSO4
You know that you can just google it right? It has this converter.
Oxygen,carbon,hydrogen,and nitrogen- together make up 95 percent of the mass of the human body.
Hope this helps.
The elements present in Ammonium Nitrate are Hydrogen, Nitrogen, and Oxygen at a ratio of 4:2:3, respectively. Hydrogen weighs in at 1.008 amu, Nitrogen at 14.007, and Oxygen at 15.999. This means that the molar mass would be:
Hydrogen
4 x 1.008 = 4.032 amu
Nitrogen
2 x 14.007 = 28.014 amu
Oxygen
3 x 15.999 = 47.997 amu
Total
4.032 + 28.014 + 47.997 = 80.043 amu
The molar mass of Ammonium Nitrate is 80.043 grams per mole.
