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3 years ago

Which expression is equivalent to (7x – 5) – (3x - 2)

Mathematics

1 answer:

Nastasia [14]3 years ago

3 0

Answer:

Step-by-step explanation:

We have the expression

$(7x-5)-(3x-2)$

First we need to distribute the negative throughout the parenthesis. Then we can combine like terms in order to simplify this expression

$(7x-5)-(3x-2)\\\\7x-5-3x+2\\\\4x-3$

This answer matches D.

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A ball is launched upward from the ground with an initial velocity of 20 ft/s. The height of the ball at time t is represented b

Anastaziya [24]

Answer:

1.-t₁ = 0,625 s

2.-h(max) = 6,25 f

3.-t = 1,25 s

Step-by-step explanation:

V₀ = 20 f/s

h(t) = - 16*t² + 20*t

h(max) = ??

h´(t) = - 32*t + 20

h(max) will occurs when V = 0 dh/dt = 0 then

- 32*t + 20 = 0

- 32*t = -20

t = 20/32

t₁ = 0,625 s

h(max) = h(0,625) = - 16*(0,625)² + 20*0,625

h(max) = - 6,25 + 12,5

h(max) = 6,25 f

c) The ball will hit the ground

t = 2*t₁

t = 2*0,625

t = 1,25 s

8 0

3 years ago

What is the slope of a line perpendicular to the line whose equation is 6x+2y=−32. Fully simplify your answer.

Reika [66]

The slope of the line that is perpendicular to 6x + 2y = -32 is: 1/3.

<h3>What is the Slope of Perpendicular Lines?</h3>

The slope of two lines that are perpendicular to each other will always have a product that is equal to -1, which means that their slopes are negative reciprocals to each other.

Rewrite 6x + 2y = -32 in slope-intercept form:

2y = -6x - 32

2y/2 = -6x/2 - 32/2

y = -3x - 16

The slope is -3. Negative reciprocal of -3 is 1/3.

Therefore, the slope of the perpendicular line would be: 1/3.

Learn more about the slope of perpendicular lines on:

brainly.com/question/1362601

#SPJ1

5 0

1 year ago

I need help ASAP <br> Integrated math II

Molodets [167]

Answer:

$\boxed{ \bold{ \sf{x = 16}}}$

$\boxed{ \bold{ \sf{m < AFD = 82}}}$

Step-by-step explanation:

$\sf{5x + 18 = 3x + 50}$

( Being vertically opposite angles)

Vertically opposite angles are always equal.

Move variable to L.H.S and change it's sign

Similarly, Move constant to R.H.S and change it's sign

⇒ $\sf{5x - 3x = 50 - 18}$

Collect like terms

⇒ $\sf{2x = 50 - 18}$

Subtract 18 from 50

⇒ $\sf{2x = 32}$

Divide both sides of the equation by 2

⇒ $\sf{ \frac{2x}{2} = \frac{32}{2} }$

Calculate

⇒ $\sf{x = 16}$

The value of x is 16

Now, let's find value of m<AFD :

$\sf{m < afd + 5x + 18 = 180}$ ( sum of angle in straight line )

plug the value of x

⇒ $\sf{m < AFD + 5 \times 16 + 18 = 180}$

Multiply the numbers

⇒ $\sf{m < AFD + 80 + 18 = 180}$

Add the numbers

⇒ $\sf{m < AFD + 98 = 180}$

Move constant to R.H.S and change it's sign

⇒ $\sf{m < AFD = 180 - 98}$

Subtract 98 from 180

⇒ $\sf{m < AFD = 82}$

Value of m<AFD = 82

Hope I helped!

Best regards!!

3 0

3 years ago

A museum has a wax sculpture of a historical village. The scale is 1.5:8. If the height of a hut in the sculpture is 5 feet, how

Oksi-84 [34.3K]

Let us say that x is the real height of the original hut, therefore we can establish the equation:

5 : x = 1.5 : 8

5 / x = 1.5 / 8

Solving for x:

x = 5 * 8 / 1.5

x = 40 / 1.5

4 0

3 years ago

Two trains travel at right angles to each other after leaving the same train station at the same time. Two hours later they are

Alex787 [66]

Answer:

15 miles per hour is the speed of the slower train.

Step-by-step explanation:

As given in the figure attached,

Let the speed of train 1 is v and train 2 is u.

Therefore, distance traveled in 2 hours by train 1 will be = 2v miles

and distance traveled by train 2 will be = 2u miles

Now we can see in the figure a right angle triangle is formed by the two trains.

AB² + BC² = AC²

(2v)² + (2u)²= (65.30)²

4v² + 4u² = 4264.09

Now we divide this equation by 4

v² + u² = 1066.02

If speed of the slower train is v miles per hour then as per statement of the question.

u = v - 14

v = u + 14

By putting the value of v in the equation

(u + 14)² + u² = 1066

u² + 196 + 28u + u² = 1066

2u² + 28u + 196 = 1066

2u² + 28u + 196 - 1066 = 0

2u² + 28u - 870 = 0

By diving this equation by 2

u² + 14u - 435 = 0

u² + 29u - 15u - 435 = 0

u(u + 29) - 15(u + 29) = 0

(u + 29)(u - 15) = 0

u = -29, 15

Since speed can not be with negative notation so u = 15 miles per hour will be the speed.

Therefore, 15 miles per hour is the speed of the slower train.

5 0

3 years ago