Given the particle's acceleration is

with initial velocity

and starting at the origin, so that

you can compute the velocity and position functions by applying the fundamental theorem of calculus:


We have
• velocity at time <em>t</em> :

• position at time <em>t</em> :

Current= voltage divided by resistance
120/30=4
Answer:
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Explanation:
Answer:
The mass of the air to produce the work
m = 8.034 kg
Explanation:
Using the equation of work and energy in the system can find the mass of air needed to produce that work
T₁ = 273 °K + 257 ° C
T₁ = 530 °K , c₁ = 0.718
Eₙ - E₀ = Δ E system
- W₀ = ΔU
- W₀ = m * (u₂ - u₁)
T₂ = T₁ * (P₂ / P₁) ⁰²⁸⁶
T₂ = 530 ° K * (100 kPa / 400 kPa )⁰²⁸⁶
T₂ = 356.66 ° K
W₀ = m * c₁ * ( T₁ - T₂)
m = W₀ / [ c₁ * ( T₁ - T₂) ]
m = 1000 kJ / 0.718 * ( 530 - 356.66) ° K
m = 8.034 kg
Answer:
Explanation:
When the spring is compressed by .80 m , restoring force by spring on block
= 130 x .80
= 104 N , acting away from wall
External force = 82 N , acting towards wall
Force of friction acting towards wall = μmg
= .4 x 4 x 9.8
= 15.68 N
Net force away from wall
= 104 -15.68 - 82
= 6.32 N
Acceleration
= 6.32 / 4
= 1.58 m / s²
It will be away from wall
Energy released by compressed spring = 1/2 k x²
= .5 x 130 x .8²
= 41.6 J
Energy lost in friction
= μmg x .8
= .4 x 4 x 9.8 x .8
= 12.544 J
Energy available to block
= 41.6 - 12.544 J
= 29 J
Kinetic energy of block = 29
1/2 x 4 x v² = 29
v = 3.8 m / s
This will b speed of block as soon as spring relaxes. (x = 0 )