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Naily [24]
3 years ago
8

A proton moves with a velocity of v with arrow = (3î − 5ĵ + k) m/s in a region in which the magnetic field is B with arrow = (î

+ 2ĵ − k) T. What is the magnitude of the magnetic force this particle experiences?
Physics
1 answer:
Allisa [31]3 years ago
7 0

Answer:

The magnitude of the magnetic force this particle experiences is 2.6\times10^{-9}\ N.

Explanation:

Given that,

Velocity v= (3i-5j+k) m/s

Magnetic field B=(i+2j-k) T

We need to calculate the value \vec{v}\times\vec{B}

(\vec{v}\times\vec{B})=3i+4j+11k

We need to calculate the magnitude of the magnetic force this particle experiences

Using formula of magnetic force

\vec{F}=q(\vec{v}\times\vec{B})

Put the value into the formula

\vec{F}=1.6\times10^{-19}\times(3i+4j+11k)

\vec{F}=(4.8i+6.4j+1.76k)\times10^{-19}

|F|=2.6\times10^{-9}\ N

Hence, The magnitude of the magnetic force this particle experiences is 2.6\times10^{-9}\ N.

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To find the answer, we have to know about the width of the central maximum.

<h3>How to find the distance between slit and the screen?</h3>
  • It is given that, wavelength 560 nm passes through a slit of width 0. 170 mm, and the width of the central maximum on a screen is 8. 00 mm.
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Learn more about the width of the central maximum here:

brainly.com/question/13088191

#SPJ4

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