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77julia77 [94]
3 years ago
14

I am greater than 27. I am less than 30. I have 9 ones

Mathematics
1 answer:
Nonamiya [84]3 years ago
6 0

Answer:

29

Step-by-step explanation:

29 > 27

29 < 30

29 has 9 ones because there is a 9 in the ones place

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Helen rolls a dice and flips a coin. <br> calculate the probability
butalik [34]

Answer:

1/12

Step-by-step explanation:

dice rolling=1/6

coin flipping=1/2

Hence probability=1/6×1/2

4 0
2 years ago
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For how many positive values of n are both n3 and 3n four-digit integers?
AVprozaik [17]

Answer:

No positive value of n

Step-by-step explanation:

we have to find out for how many positive values of n are both

n^3 , 3^n our-digit integers

Let us consider first cube

we get 4digit lowest number is 1000 and it has cube root as 10.

Thus 10 is the least integer which satisfies four digits for cube.

The highest integer is 9999 and it has cube root as 21.54

or 21 the highest integer.

Considering 3^n we get,

3^10 is having 5 digits and also 3^21

Thus there is no positive value of n which satisfy that both n cube and 3 power n are four digits.

5 0
3 years ago
Find x. Give reasons to justify your solution. b Lines AB and CD are straight lines.
MArishka [77]

Answer:

x = 28

Step-by-step explanation:

Given that lines AB and CD are straight lines that intersects at O, it follows that the pair of opposite vertical angles formed are congruent.

Thus,

<AOD = <BOC

<AOD = 152°

<BOC = 3x + x + (x + 12) (angle addition postulate)

<BOC = 5x + 12

Since <AOD = <BOC, therefore,

152° = 5x + 12 (substitution)

152 - 12 = 5x (subtraction property of equality)

140 = 5x

140/5 = x (division property of equality)

28 = x

x = 28

4 0
3 years ago
If (ax^2 + 3x + 2b) - (5x^2+bx-3c)=3x^2-9, what is the value of A + B + C?
Rina8888 [55]

Answer:

We have the equation:

(ax^2 + 3x + 2b) - (5x^2+bx-3c)=  3x^2 - 9

First, move all to the left side.

(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0

Now let's group togheter terms with the same power of x.

(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.

This must be zero for all the values of x, then the things inside each parenthesis must be zero.

1)

a - 5 - 3 = 0

a = 3 + 5 = 8.

2)

3 - b = 0

b = 3.

3)

2b + 3c + 9 = 0

2*3 + 3c + 9 = 0

3c = -6 - 9 = -15

c = -15/3 = -5

Then we have:

a = 8, b = 3, c = -5

a + b + c = 8 + 3 - 5 = 6

8 0
3 years ago
PLEASE PLEASE HELP ITS A TIMED QUIZ
masha68 [24]

Answer:

No there is not

Step-by-step explanation:

6 0
3 years ago
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