n, n + 2, n + 4 - three consecutive even integers
n + 2 = 2(n + 4) - 6 |use distributive property
n + 2 = (2)(n) + (2)(4) - 6
n + 2 = 2n + 8 - 6
n + 2 = 2n + 2 |subtract 2 from both sides
n = 2n |subtract 2n from both sides
-n = 0
n = 0
n + 2 = 0 + 2 = 2
n + 4 = 0 + 4 = 4
Answer: 0, 2, 4.
Answer:
Its C i think
Step-by-step explanation:
The answer I believe is -2. Thank you come again
