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Softa [21]
3 years ago
8

F P(A)= 0.70 and P(B) = 0.20, then A and B are independent events if?

Mathematics
1 answer:
german3 years ago
5 0

Answer:

They are independent if the sum is an even number.

Step-by-step explanation:

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PLEASE HURRY!! The graph shows the distance traveled by two cars over several minutes.
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Im late but i had this test its car A < rate of car B hope it helps
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3 years ago
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The graph of F(x), shown below, has the same shape as the graph of
yarga [219]

Answer:

x^3-1

Step-by-step explanation:

f(x)=g(x)-1 since was shifted down 1 unit                                        x^3-1

f(x)=g(x)+1 would have been a shift up of 1 unit                             x^3+1

f(x)=g(x-1) shifted right 1 unit                                                            (x-1)^3

f(x)=g(x+1) shifted left one unit                                                        (x+1)^3

Anyways the answer is f(x)=x^3-1

8 0
3 years ago
Sarah biked the same distance each day for 6 days. If she traveled 468 kilometers altogether, how many kilometers did she travel
I am Lyosha [343]
76 kilometers per day.

Step by step

468 divided by 6 = 76

76•6=468
8 0
3 years ago
Assume that​ women's heights are normally distributed with a mean given by mu equals 62.5 in​,and a standard deviation given by
Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with  

\mu = 62.5 in

\sigma = 2.2 in

the normal probability density function is given by  

f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}, then

(a) P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx = 0.5899

   (in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking P(\bar{X} < 63) where n = 37. \bar{X} is normally distributed with mean 62.5 in and standard deviation 2.2/\sqrt{37}. So, the probability density function is given by

g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}, and

P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0
3 years ago
I’ll mark you as a brain list please help
pochemuha

Answer:

just ignore this whole thing

3 0
3 years ago
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