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Jet001 [13]
3 years ago
7

When is a sailboat the stand on vessel in relations to a recreational power boat?

Physics
1 answer:
qwelly [4]3 years ago
8 0
The stand-on vessel is the one that is on the starboard side of a boat, and its red light or streamer is visible to you. The situation where a sailboat would be the stand-on vessel will be then the sailboat is overtaking the power boat.

The opposite of a stand-on vessel is the give-way vessel, which is on the port side, the green light or streamer of which is visible to you.
You might be interested in
is it possibly to make special swords made out of light that can cute through anything like in the movie star wars?
g100num [7]
No because light travels in waves and can not stop 3 feet away an having power supplied like that
6 0
3 years ago
How much time does it take for a car traveling at 65 miles/hour to travel 300 miles
galina1969 [7]

Time taken by the car to travel 300 miles is 4.615 hours.

<h3>What is speed?</h3>

The speed of any moving object is the ratio of the distance traveled and the time taken to cover that distance.

Given is the distance d = 300 miles and the speed s = 65 miles/hour, then the time taken t will be

s=d/t

65 = 300/t

t= 4.615 hours

Thus, time taken by the car to travel 300 miles is 4.615 hours.

Learn more about speed.

brainly.com/question/7359669

#SPJ4

5 0
2 years ago
A car has 10,800 kg m/s of momentum as it collides with a trash dumpster AT REST.
Delvig [45]

Answer:

10800 kg m/s

Explanation:

Since the dumpster was initially at rest, its momentum before collision equal to zero. So that the total momentum of the car and dumpster before collision is 10800 kg m/s.

The principle of conservation of linear momentum states that: in a system of colliding bodies, total momentum is conserved. Therefore, the total momentum of the car and dumpster after collision is 10800 kg m/s.

3 0
3 years ago
In a race, Usain Bolt accelerates at
jeka94

Answer:

65.87 s

Explanation:

For the first time,

Applying

v² = u²+2as.............. Equation 1

Where v = final velocity, u = initial velocity, a = acceleration, s = distance

From the question,

Given:  u = 0 m/s (from rest), a = 1.99 m/s², s = 60 m

Substitute these values into equation 1

v² = 0²+2(1.99)(60)

v² = 238.8

v = √238.8

v = 15.45 m/s

Therefore, time taken for the first 60 m is

t = (v-u)/a............ Equation 2

t = (15.45-0)/1.99

t = 7.77 s

For the final 40 meter,

t = (v-u)/a

Given: v = 0 m/s(decelerates), u = 15.45 m/s, a = -0.266 m/s²

Substitute into the equation above

t = (0-15.45)/-0.266

t = 58.1 seconds

Hence total time taken to cover the distance

T = 7.77+58.1

T = 65.87 s

3 0
3 years ago
An electron is pushed into an electric field where it acquires a 1-V electrical potential. Suppose instead that two electrons ar
sleet_krkn [62]

Answer:

0.5 V

Explanation:

The electric potential distance between different locations in an electric field area is unaffected by the charge that is transferred between them. It is solely dependent on the distance. Thus, for two electrons pushed together at the same distance into the same field, the electric potential will remain at 1 V. However, the electric potential of one of the two electrons will be half the value of the electric potential for the two electrons.

6 0
3 years ago
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