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Vinvika [58]
4 years ago
6

At normal temperature and pressure, air has

Physics
1 answer:
lisabon 2012 [21]4 years ago
7 0
0.001184 g/mL = 0.001184 x 1000 ml/L x 1/1000 kg/g
= 0.001184 kg/L

Volume of room:
2.84 x 2.27 x 2.71
= 17.47 m³ = 17470 L

Mass of air = density x volume
= 0.001184 x 17470
= 20.7 kg
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Find the circumference of a circle whose area is 452.16 square meters. (Use 3.1416 as the value of .)
kakasveta [241]

1) The area of a circle is given by

A=\pi r^2

where r is the radius of the circle. In this problem, we are told that the area is

A=452.16 m^2

so we can rearrange the previous equation to calculate the radius:

r=\sqrt{\frac{A}{\pi}}=\sqrt{\frac{452.16 m^2}{3.1416}}=12.0 m


And now we can find the circumference, by using the formula:

c=2 \pi r=2 \pi (12.0 m)=75.3984 m

Therefore, the correct answer is D. 75.3984 meters.



2) The volume of a cube is given by:

V=L^3

where L is the length of the edge. In this problem, L=6 cm, therefore the volume of the cube is

V=L^3=(6 cm)^3=216 cm^3


and so, the correct answer is A. 216 cu. cm.

5 0
4 years ago
a bag of cement is pulled along a horizontal plane by a constant force of 15n calculate the work done in moving the bag through
morpeh [17]

Answer:

300J

Explanation:

Given parameters:

Constant force = 15N

Distance  = 20m

Unknown:

Work done   = ?

Solution:

Work done is the force applied to move a body through a particular distance.

 Work done  = Force x distance

 So;

  Work done  = 15 x 20  = 300J

4 0
3 years ago
In a loading a lorry a man lifts boxes each weight 200N through a height of 3.5m.
vekshin1

The work done on the boxes and the energy spent is 700J while the power required to lift 4 boxes per minute is 2.8kW

This work done on an object is the force required to move that object from point A to point B.

Data Given;

  • Weight (mg) = 200N
  • Distance (s) = 3.5m
<h3>Work Done</h3>

This is the work done to move the boxes from point A to point B.

w = F.s\\F = ma = mg = 200N\\w = 200 * 3.5\\w = 700J

The work done to move the object is 700J

<h3>Energy</h3>

This is used to calculated the energy used to carry the work done and the formula is given as

E = force * displacement\\E = F.s\\E = 200 * 3.5\\E = 700J

The energy transferred when he lifts one box is 700J

<h3>Power</h3>

Power is the rate at which energy is used with respect to time

P = E/t\\

The energy required to lift 4 boxes in one minutes is

700 * 4 = 2800

Now we can calculate the power used

P = Energy / time\\P = 2800 / 1 \\P = 2800W = 2.8kW

The power required to move four boxes in 1 minutes is 2.8kW

From the calculations above, the following was gotten

  • work done = 700J
  • Energy = 700J
  • Power = 2800W or 2.8kW

Learn more on work done, energy and power here;

brainly.com/question/10063455

4 0
3 years ago
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