Electroreception is limited to aquatic environments because on here is the resistivity of the medium is low enough for electric currents to be generated as the result of electric fields of biological origin. In air, the resistivity of the environment is so high that electric fields from biological sources do not generate a significant electric current. Electroreceptor are found in a number of species of fish, and in at least one species of mammal, the Duck-Billed platypus.
The total distance you would have covered is equivalent to going around the earth 22 times.
<h3>
Total distance traveled</h3>
The total distance traveled at a given speed and time of motion is calculated as follows;
Distance = speed x time

<h3>Distance round the Earth</h3>
The distance round the earth or circumference of the earth of the earth has been given as 25,000 miles
<h3>Number of times round the earth</h3>

Thus, the total distance you would have covered is equivalent to going around the earth 22 times.
Learn more about distance here: brainly.com/question/17273444
Answer:
Explanation:
Component of force F₁ in right direction = F₁cos37
= 12 x cos37 = 9.58 N .
Component of force F₂ in vertically upward direction = F₁sin37
= 12 x sin37 = 7.22 N .
a ) Let normal force be R
R + F₁sin37 = mg
R + 7.22 = 1.5 x 9.8 = 14.7
R = 7.48 N .
b )
Net force in horizontal direction = F₂ - F₁cos37
= F₂ - 9.58
This is equal to zero as body is moving with zero acceleration
F₂ - 9.58 = 0
F₂ = 9.58 N
c ) If body is moving with acceleration of 2.5 m /s² along the direction of F₂
F₂ - 9.58 = 1.5 x 2.5 = 3.75
F₂ = 13.33 N .
Answer:
Factor = 8.77
Explanation:
Fraction of collision with energy greater than or equal to the activation energy can be given by the formula:


R = 8.314 J/mol.K
When Temperature = 34⁰C = 34 + 273 = 307 K

When Temperature = 52⁰C = 52 + 273 = 325 K


Factor = 8.77
From the calculation, the force constant is 192 N. Also, friction would decrease the extension.
<h3>What is the force constant?</h3>
We know that the force constant can be obtained by the use of the relation;
F = Ke
F = applied force
K = force constant
e = extension
We know from Hooks law that the force applied is directly proportional to the extension.
We can write;
F = mgcosθ
F = 43 Kg * 9.8 m/s^2 * sin31°
F = 217 N
K = 217 N/1.13 m
K = 192 N/m
If there is friction between the incline and the crate, it will stretch less because some work will be lost due to friction causing only some fraction of the elastic potential energy to be converted to kinetic energy.
Learn more about Hooke's law:brainly.com/question/14140269
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