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2 years ago

13

Quanto fa 2 +2 ,qualcuno capisce l’italiano?

2 answers:

creativ13 [48]2 years ago

6 0

Answer:

i dont know which language is this but the answer is 4

BabaBlast [244]2 years ago

5 0

Answer:

4

Step-by-step explanation:

2 + 2 is 4

hop3 it helps.....

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What is five and one third divided by four

Stella [2.4K]

It is 1.3333333333 repeated

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3 years ago

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I WILL GIVE A BRANLIEST!<br>What is the graph of the functions?<br> y=2*2^x<br> y=-2*5^x

tekilochka [14]

For this case what you should know is that both functions are of the potential type.
We have then that
y = 2 * 2 ^ x
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y = -2 * 5 ^ x
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Answer
See attached graphics.

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2 years ago

Use triangle ABC drawn below & only the sides labeled. Find the side of length AB in terms of side a, side b & angle C o

Brrunno [24]

Answer:

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

$Sin\ C = \frac{h}{a}$

Make h the subject:

$h = aSin\ C$

Also, in BOC (Using Pythagoras)

$a^2 = h^2 + x^2$

Make $x^2$ the subject

$x^2 = a^2 - h^2$

Substitute $aSin\ C$ for h

$x^2 = a^2 - h^2$ becomes

$x^2 = a^2 - (aSin\ C)^2$

$x^2 = a^2 - a^2Sin^2\ C$

Factorize

$x^2 = a^2 (1 - Sin^2\ C)$

In trigonometry:

$Cos^2C = 1-Sin^2C$

So, we have that:

$x^2 = a^2 Cos^2\ C$

Take square roots of both sides

$x= aCos\ C$

In triangle BOA, applying Pythagoras theorem, we have that:

$AB^2 = h^2 + (b-x)^2$

Open bracket

$AB^2 = h^2 + b^2-2bx+x^2$

Substitute $x= aCos\ C$ and $h = aSin\ C$ in $AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2$

Open Bracket

$AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C$

Reorder

$AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C$

Factorize:

$AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C$

In trigonometry:

$Sin^2C + Cos^2 = 1$

So, we have that:

$AB^2 = a^2 * 1 + b^2-2abCos\ C$

$AB^2 = a^2 + b^2-2abCos\ C$

Take square roots of both sides

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

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3 years ago

the metro theater has 20 rows of seats with 18 seats I each row. Ticket cost $5. the theater's income in dollars if all seat are

Mumz [18]

500 IS THE ANSWER XD

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2 years ago

Find the measure of angle x in the figure below<br>67 61<br>у<br>X<br>67

kondor19780726 [428]

Answer: y67

Step-by-step explanation:5n − 19 + n + 7 = 144 − 6n

6n − 12 = 144 − 6n

12n = 156

n = 13

m∠z = (144−6n)°

m∠z = (144−6×13)°

m∠z = y67

3 0

3 years ago

Read 2 more answers