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3 years ago

Quanto fa 2 +2 ,qualcuno capisce l’italiano?

Mathematics

2 answers:

creativ13 [48]3 years ago

6 0

Answer:

i dont know which language is this but the answer is 4

BabaBlast [244]3 years ago

5 0

Answer:

Step-by-step explanation:

2 + 2 is 4

hop3 it helps.....

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Write a conditional statement. Write the converse, inverse and contrapositive for your statement and determine the truth value o

photoshop1234 [79]

A conditional statement involves 2 propositions, p and q. The conditional statement, is a proposition which we write as: p⇒q,

and read "if p then q"

Let p be the proposition: Triangle ABC is a right triangle with m(C)=90°.

Let q be the proposition: The sides of triangle ABC are such that

$|AB|^2=|BC|^2+|AC|^2$ .

An example of a conditional statement is : p⇒q, that is:

if Triangle ABC is a right triangle with m(C)=90° then The sides of triangle ABC are such that $|AB|^2=|BC|^2+|AC|^2$

This compound proposition (compound because we formed it using 2 other propositions) is true. So the truth value is True,

the converse, inverse and contrapositive of p⇒q are defined as follows:

converse: q⇒p
inverse: ¬p⇒¬q (if [not p] then [not q])
contrapositive: ¬q⇒¬p

Converse of our statement:

if The sides of triangle ABC are such that $|AB|^2=|BC|^2+|AC|^2$
then Triangle ABC is a right triangle with m(C)=90°

True

Inverse of the statement:

if Triangle ABC is not a right triangle with m(C) not =90° then The sides of triangle ABC are not such that $|AB|^2=|BC|^2+|AC|^2$

True

Contrapositive statement:

if The sides of triangle ABC are not such that $|AB|^2=|BC|^2+|AC|^2$ then Triangle ABC is not a right triangle with m(C)=90°

True

4 0

3 years ago

Graph the hyperbola using the transverse axis, vertices, and co-vertices:

Reptile [31]

See attachment for the graph of the hyperbola 12x^2 - 3y^2 - 108 = 0

<h3>How to graph the hyperbola?</h3>

The equation of the hyperbola is given as:

12x^2 - 3y^2 - 108 = 0

Start by calculating the transverse axis

So, we have:

<u>Transverse axis</u>

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

Where

a = 3 and b = 6

The transverse axis is calculated as:

y = ±b/a(x - h) + k

So, we have:

y = ±6/3(x - 0) + 0

Evaluate the difference and sum

y = ±6/3x

Evaluate the quotient

y = ±2x

This means that the transverse axes are y = 2x and y =-2x

<u>The vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

<u>The co-vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

And

a = 3 and b = 6

The co-vertices are

(h - a, k) and (h + a, k)

So, we have:

(0 - 3, 0) and (0 + 3, 0)

Evaluate

(-3,0) and (3, 0)

See attachment for the graph of the hyperbola