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hoa [83]
4 years ago
5

Need help solving -3^4x-3^4/(-3^2)^3

Mathematics
1 answer:
riadik2000 [5.3K]4 years ago
3 0

Answer:

The solved given expression is

\frac{-3^4x-3^4}{(-3^2)^3}=-\frac{(x+1)}{9}

Step-by-step explanation:

Given expression is \frac{-3^4x-3^4}{(-3^2)^3}

To solving the given expression as below :

\frac{-3^4x-3^4}{(-3^2)^3}

\frac{-3^4x-3^4}{(-3^2)3}=\frac{3^4(-x-1)}{(-3^2)3}

=\frac{-3^4(x+1)}{(3^2)3}  ( by using the property (a^m)^n=a^{mn} )

=\frac{-3^4(x+1)}{3^6}

=\frac{-(x+1)}{3^6.3^{-4}}  ( by using the property a^m=\frac{1}{a^{-m}} )

=\frac{-(x+1)}{3^{6-4}} ( by using the property a^m.a^n=a^{m+n}  )

=-\frac{(x+1)}{3^2}

=-\frac{(x+1)}{9}

Therefore \frac{-3^4x-3^4}{(-3^2)^3}=-\frac{(x+1)}{9}

Therefore the solved given expression is

\frac{-3^4x-3^4}{(-3^2)^3}=-\frac{(x+1)}{9}

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