A gas mixture contains rn, he and n2. what is the total pressure of the mixture, if the mole fraction of n2 is 0.350 and the pre
ssure of n2 is 0.580 atm?
1 answer:
We can solve this problem using Raoults law. The formula
for Raoults law is:
P_a = X_a * P
where,
P_a = the partial pressure of substance A
X_a = the mole fraction of substance A
P = total pressure
Therefore calculating for P:
P = P_a / X_a
P = 0.580 atm / 0.35
<span>P = 1.657 atm</span>
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