Answer:
0.7
Explanation:
Using Hardy-Weinberg equation of genetic variation being constant when disturbing factors such has mutation and others are removed.
p² + pq + q² = 1 and p + q = 1
where p² is the frequency of the homozygous dominant genotype (RR) and q² is the frequency of the homozygous recessive genotype (rr) and 2pq is the frequency of heterozygous genotype (Rr). p represent the frequency of "R" and q represent "g". since the coefficient against the green/green homozygote is 0.30 then
the fitness of the green/green homozygote = 1 - 0.3 = 0.7
The genes to be resistant to an antibiotic already exist in the bacteria's genes. Those whose phenotypes are resistant to the antibiotic will survive the antibiotic which kills the other non-antibiotic-resistant bacteria. The surviving bacteria will then asexually reproduce, producing more antibiotic-resistant bacteria.
Answer:
these differentiate as a result of signaling mechanisms. ... The daughter cells divides and after each division it becomes more specialized. When it reaches a mature cell type downstream (for example, becomes a red blood cell) it will no longer divide.
It’s the last one emissions ejected out from smokestacks
