-30b4 would be your answer.
Hope I helped!
Answer:
A. =4x3+9x2−25x+12
Step-by-step explanation:
(x+4)(4x−3)(x−1)
=((x+4)(4x−3))(x+−1)
=((x+4)(4x−3))(x)+((x+4)(4x−3))(−1)
=4x3+13x2−12x−4x2−13x+12
=4x3+9x2−25x+12
No 11.473 is greater then 11.447
Answer:
1/4 = (5n)/(n +95)
Step-by-step explanation:
If all the numbers referred to are the same number, we can use n to represent it. Then, "the ratio of a number and 4 times that number" is n/(4n) = 1/4. "The ratio of 5 times the number and 95 more than the number" is (5n)/(n+95)
The equation for the problem can be written ...
1/4 = (5n)/(95+n)
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If you're a purist, you might leave the factors of "a number" in the first raio and write it ...
n/(4n) = (5n)/(95+n)
Solving this gets you to a quadratic form that has the extraneous solution n=0.
Answer:
x = 3π/4, 5π/4
Step-by-step explanation:
cos(x+2π) = -√2/2, [0,2π]
cos(x)cos(2π)-sin(x)sin(2π) = -√2/2
cos(x) = -√2/2
x = 3π/4, 5π/4
Remember that the cosine function is periodic, so cos(θ+2π)=cos(θ).
