Question

An object was thrown from 60 feet high. The equation h=-16t2+60

Answer 1

Answer:

1.9 Seconds

Step-by-step explanation:

The equation that models the height of the object is given as:

$h=-16t^2+60$

The object will land when its height, h(t)=0

$\text{When h(t)=0}\\-16t^2+60=0\\-16t^2=-60\\ Divide both sides by -16\\\dfrac{-16t^2}{-16} =\dfrac{-60}{-16}\\t^2=3.75\\t=\sqrt{3.75} \\t=1.94\:seconds\\\approx 1.9\:seconds (to the nearest tenth)$

The object will land after 1.9 seconds.