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babymother [125]
3 years ago
9

PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
3 0

log_{7}(49)  = 2

V125BC [204]3 years ago
3 0

Answer:

2 = log7 (49)

Step-by-step explanation:

7^2 = 49

Take the log base 7 on each side

log7 (7^2) = log7 (49)

2 = log7 (49)

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The number of fish in a lake decreased by 20% between last year and this year. Last year there were 75 fish in the lake. What is
7nadin3 [17]

Answer:

90

Step-by-step explanation:

75 × (20/100) = 15

75+15=90

7 0
3 years ago
Based on the labels in the diahram of the human eye,the reader can conclude that
lesantik [10]
What are you asking
5 0
3 years ago
5x + 2y = -3<br>3x + 3y = 9​
Karolina [17]

Answer:

Step-by-step explanation:

5x + 2y = -3

3x + 3y = 9

15x + 6y = -9

-15x - 15y = -45

-9y = -54

y = 6

5x + 2(6) = -3

5x + 12 = -3

5x = -15

x = -3

(-3, 6)

6 0
3 years ago
Question attached as screenshot below:Please help meI am following along
Ludmilka [50]

Given

x=0 and x =10 and x1, x2, x3, x4 are the midpoints of five equal intervals

Answer

The 5 equal intervals are 2 , 4 , 6, 8 10

Mid points are 1, 3 , 5 , 7 , 9

Option B is correct

3 0
1 year ago
2. Find the 20th term of an arithmetic sequence if its 6th term is 14 and 14th term is 6.
Fudgin [204]

Answer:

\sf t_{20}= 0

Step-by-step explanation:

<h3>Arithmetic sequence:</h3>

      \sf \boxed{\bf n^{th} \ term = a + (n-1)d}\\\\\text{Here, a is the first term ; d is the common difference }

6th term is 14 ⇒ \sf t_6 = 14

                a + (6 - 1)d = 14

                    a  +  5d = 14  --------------(I)

14th term is 6 ⇒\sf t_{14} = 6

             a + (14-1)d = 6

                  a + 13d = 6 ----------------(II)

Subtract equation (II) from equation(I)

        (I)          a + 5d = 14

        (II)         a + 13d = 6

                    <u>-    -          -</u>

                            -8d = 8

                               d  = 8 ÷(-8)      

                              \sf \boxed{\bf d= (-1)}

Plugin d = -1 in equation (I)

a + 5(-1) = 14

      a -5  = 14

             a = 14 + 5

             \sf \boxed{\bf a = 19}  

20th term:

 \sf t_{20}= 19 + 19*(-1)

       = 19 - 19

   \sf \boxed{\bf t_{20} = 0}

8 0
2 years ago
Read 2 more answers
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