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mina [271]
3 years ago
9

Which of the following may be used by employers to inform workers about hazardous materials

Chemistry
1 answer:
ivann1987 [24]3 years ago
6 0

I would go with C. SDS and warning signs

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How does a limiting reagent affect how much product is formed?
Anna35 [415]

Answer: C

Explanation:

4 0
3 years ago
Read 2 more answers
NH4+(aq) + NO2−(aq) → N2(g) + 2H2O(l) is given by rate = k[NH4+][NO2−]. At a certain temperature, the rate constant is 4.10 × 10
arlik [135]

Answer:

rate = 1.97\times 10^{-5}\ M/s

Explanation:

Given that:-

rate = k[NH_4^+][NO_2^-]

k = 4.10\times 10^{-4}\ /Ms

[NH_4^+]=0.301\ M

[NO_2^-]=0.160\ M

So,

rate = 4.10\times 10^{-4}\times 0.301\times 0.160\ M/s=1.97\times 10^{-5}\ M/s

<u>1.97\times 10^{-5}\ M/s is the rate of the reaction at that temperature if [NH4+] = 0.301 M and [NO2−] = 0.160 M.</u>

8 0
3 years ago
Which is the correctly balanced chemical equation for the reaction of KOH and H2SO4?
Ksenya-84 [330]

Answer:

3) 2KOH + H2SO4 → K2SO4 + 2H2O

Explanation:

The balanced chemical equation for the reaction of KOH and H2SO4 is,

→ 2KOH + H2SO4 → K2SO4 + 2H2O

Hence, option (3) is the correct answer.

5 0
3 years ago
Identify the element that has 6 valence electrons and 3 energy levels
evablogger [386]

Answer:

Sulfur

Explanation:

<u>Valence electrons</u> are the group numbers. The group numbers are the numbers that go from left to right on the top. But since you can't have more than 8 valence electrons, the group numbers of 13-18, the valence electrons will actually be from 3-8. So 6 valence electrons would be group 16. That narrows it down a lot. The only elements in this group are oxygen, sulfur, selenium, tellurium, polonium, and livermorium.

Energy level are the period numbers. The period numbers are the numbers that go from top to bottom. So the 3rd energy level is the 3rd period. So when you look at the periodic table, under the 16 group and 3rd period, lies Sulfur.

5 0
3 years ago
Write the balanced equation for the oxidation of isoborneol by naocl
TiliK225 [7]
  the balanced  equation  for  oxidation  of  isoborneol   by  naocl  is  written  as  follows

C10H18O  + NaOCl  ---->  C10H16O  +  NaCl  +   H2O

isoborneol  (C10H18O)   react   with  NaOcl    to  form  C10H16O   NaCl   and    H2O
7 0
4 years ago
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