Answer:
The final pressure is approximately 0.78 atm
Explanation:
The original temperature of the gas, T₁ = 263.0 K
The final temperature of the gas, T₂ = 298.0 K
The original volume of the gas, V₁ = 24.0 liters
The final volume of the gas, V₂ = 35.0 liters
The original pressure of the gas, P₁ = 1.00 atm
Let P₂ represent the final pressure, we get;
![\dfrac{P_1 \cdot V_1}{T_1} = \dfrac{P_2 \cdot V_2}{T_2}](https://tex.z-dn.net/?f=%5Cdfrac%7BP_1%20%5Ccdot%20V_1%7D%7BT_1%7D%20%3D%20%5Cdfrac%7BP_2%20%5Ccdot%20V_2%7D%7BT_2%7D)
![P_2 = \dfrac{P_1 \cdot V_1 \cdot T_2}{T_1 \cdot V_2}](https://tex.z-dn.net/?f=P_2%20%3D%20%5Cdfrac%7BP_1%20%5Ccdot%20V_1%20%5Ccdot%20T_2%7D%7BT_1%20%5Ccdot%20V_2%7D)
![P_2 = \dfrac{1 \times 24.0 \times 298}{263.0 \times 35.0} = 0.776969038566](https://tex.z-dn.net/?f=P_2%20%3D%20%5Cdfrac%7B1%20%5Ctimes%2024.0%20%5Ctimes%20298%7D%7B263.0%20%5Ctimes%20%2035.0%7D%20%3D%200.776969038566)
∴ The final pressure P₂ ≈ 0.78 atm.
Answer:
mass = 2.65 [nearest hundredth].
Explanation:
Mass = Density / Volume
mass = 1000 / 376.8
mass = 2.653927813163.. ≈ 2.65
Answer:
The total energy of the system is maintained as energy is transformed.
Explanation:
The total energy of the system is conserved.
Explanation 2Al2O3(s)-->4Al(s)+302(g)What is the total number of moles of O2 that are produced when 8.0 mol of Al2O3(s)are totally decomposed ?
The neutralization of the base with an acid will result to the formation of salt and water. In this case, a mole of strong acid will have one halide that will react with the Na atom. Since there are two Na atoms in each of the molecule of Na2HPO4, this will need 2 halide atoms.