This statement is true. The combining of hydrogen isotopes is indeed a fusion example. Fusion is the process of the combining two distinct entities and most fusion reactions combine hydrogen isotopes to come up with such product.
C6H6 is benzene, an organic compound. I would imagine it would be immiscible, since most organic compounds don’t dissolve in water very well.
Answer:
1. Limiting reactant.
2. Product.
3. Theoretical yield.
4. Reactants.
5. Actual yield
Explanation:
1. The limiting reactant. The limiting reactant is the reagent that is completely up in the reaction.
2. Product. Product is the result obtained From a reaction and the amount of product formed is determined by the limiting reactant
3. Theoretical yield. This is the result obtained from the stoichiometry calculations.
4. Reactant. Reactant are the starting material for a chemical reaction. The amount of the reactants determines the theoretical yield (products)
5. Actual yield. This is the result obtained from the experiment carried out in the laboratory.
Answer:
![[NO]=\frac{k_{-1}}{k_1} [N_2O_2]](https://tex.z-dn.net/?f=%5BNO%5D%3D%5Cfrac%7Bk_%7B-1%7D%7D%7Bk_1%7D%20%5BN_2O_2%5D)
Explanation:
Hello!
In this case, since the reaction may be assumed in chemical equilibrium, we can write up the rate law as shown below:
![r=-k_1[NO]+k_{-1}[N_2O_2]](https://tex.z-dn.net/?f=r%3D-k_1%5BNO%5D%2Bk_%7B-1%7D%5BN_2O_2%5D)
However, since the rate of reaction at equilibrium is zero, due to the fact that the concentrations remains the same, we can write:
![0=-k_1[NO]+k_{-1}[N_2O_2]](https://tex.z-dn.net/?f=0%3D-k_1%5BNO%5D%2Bk_%7B-1%7D%5BN_2O_2%5D)
Which can be also written as:
![k_1[NO]=k_{-1}[N_2O_2]](https://tex.z-dn.net/?f=k_1%5BNO%5D%3Dk_%7B-1%7D%5BN_2O_2%5D)
Then, we solve for the concentration of NO to obtain:
![[NO]=\frac{k_{-1}}{k_1} [N_2O_2]](https://tex.z-dn.net/?f=%5BNO%5D%3D%5Cfrac%7Bk_%7B-1%7D%7D%7Bk_1%7D%20%5BN_2O_2%5D)
Best regards!
Delta energy on labelled diagram is attached below