What is the value of 3×^2+4y^2 if x=2 y=1,and z=-3
1 answer:
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9514 1404 393
Answer:
(1) -5 and -3
Step-by-step explanation:
Descarte's rule of signs tells you the lack of sign changes among the coefficients means there are <em>no positive real roots</em>. That eliminates all answer choices except the first one.
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If you want to go to the trouble, you can factor the equation:
y = (x +3)(x +5)
These factors are zero when x = -5 and x = -3.
