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3 years ago

(16x-1) (20x+10) What is X?

Mathematics

1 answer:

KatRina [158]3 years ago

8 0

Answer:

320x^2+140x-10

Step-by-step explanation:

(16x-1)(20x+10)

320x^2+160x-20x-10

320x^2+140x-10

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(6+3)+21=6+(3+21) name each property of addition or multiplication

Anna007 [38]

(6 + 3) + 21 = 6 + (3 + 21)

It's an ASSOCIATIVE PROPERTY
(a + b) + c = a + (b + c)

7 0

4 years ago

Please do provide a correct answer because other ways I will report/block you. Please be honest and help me, please.

Irina-Kira [14]

Answer:

incomplete

Step-by-step explanation:

please send the full information, I can't see students belonging to acers

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2 years ago

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Katyanochek1 [597]

Answer:

I think A is correct answer

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3 years ago

Read 2 more answers

En un pozo petrolìfero produce cada dia 2680 barriles de petroleo. Si cada barril contiene 159 litros de petroleo, cuantos litro

Aliun [14]

Answer:

426,120 litros se producen en un día Se producen

12,783,600 litros por mes (para un cálculo de 30 días en un mes)

Step-by-step explanation:

Aquí, debemos calcular la cantidad en litros de petróleo producido en un pozo petrolero.

Se nos dice que se producen 2.680 barriles por día y cada barril contiene 159 litros de petróleo.

La producción diaria en litros es, por lo tanto, de 159 * 2680 = 426,120 litros.

Ahora, para la producción mensual, supongamos que hay 30 días en un mes, la cantidad en litros producidos por mes sería la cantidad diaria multiplicada por la cantidad de días en un mes.

Matemáticamente, eso sería 30 * 426,120 = 12,783,600 litros

4 0

4 years ago

A polymer is manufactured in a batch chemical process. Viscosity measurements show that it is approximately normally distributed

PilotLPTM [1.2K]

Answer: (751.05, 766.95)

Step-by-step explanation:

We know that the confidence interval for population mean is given by :-

$\overline{x}\pm z*\dfrac{\sigma}{\sqrt{n}}$ ,

where $\sigma$ =population standard deviation.

$\overline{x}$ = sample mean

n= sample size

z* = Two-tailed critical z-value.

Given : $\sigma= 20$

n= 42

$\overline{x}=759$

We know that from z-table , the two-tailed critical value for 99% confidence interval : z* =2.576

Now, the 99% confidence interval around the true population mean viscosity :-

$759\pm (2.5760)\dfrac{20}{\sqrt{42}}\\\\=759\pm (2.5760)(3.086067)\\\\=759\pm7.9497=(759-7.9497,\ 759+7.9497)\]\\=(751.0503,\ 766.9497)\approx(751.05,\ 766.95)$

∴ A 99% confidence interval around the true population mean viscosity : (751.05, 766.95)

3 0

4 years ago