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Anit [1.1K]
3 years ago
13

A ball on a string makes 15.0 revolutions in 6.37s, in a circle of radius 0.230m. what is its centripetal acceleration?(unit=m/s

^2) i need help please
Physics
1 answer:
Zanzabum3 years ago
7 0

Answer:

50.3 m/s²

Explanation:

Centripetal acceleration is:

a = v² / r

where v is velocity and r is radius.

First, calculate the velocity.  Velocity is distance divided by time.  The distance is the number of circumferences traveled by the ball.

v = x / t

v = (15.0 × 2π × 0.230 m) / 6.37 s

v = 3.40 m/s

Therefore:

a = (3.40 m/s)² / 0.230 m

a = 50.3 m/s²

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Answer:

t = 4.1 seconds

Explanation:

It is given that,

Width of road which is to be crossed by a man is 8.25 m, it means it is distance to be covered.

Speed of man is 2.01 m/s

We need to find the time taken by the man to cross the road. It is a concept of speed. Speed of a person is given by total distance covered divided by time taken. So,

v=\dfrac{d}{t}

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t=\dfrac{d}{v}\\\\t=\dfrac{8.25}{2.01}\\\\t=4.1\ s

So, the time taken by the man to cross the road is 4.1 seconds.

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How will the motion of a falling whirligig compare to that of a falling paper ball?
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<h3>Type of motion performed by whirligig and falling paper ball </h3>

The motion of a falling whirligig is different from the motion of a falling paper ball because the paper ball falls on the ground without spinning while on the other hand, the whirligig falls on the ground along with spinning.

The falling whirligig performs two motion i.e. one is falling on the ground and the other is spinning during motion whereas paper ball performs one motion i.e. motion in the air towards the ground so we can conclude that the motion of a falling whirligig is different than of a falling paper ball.

Learn more about motion here: brainly.com/question/453639

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I think it is Cinder Cone volcano.

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