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ivanzaharov [21]

3 years ago

8

How many days does the earth take to rotate around the sun

1 answer:

ValentinkaMS [17]3 years ago

3 0

Answer:

1 day

Explanation:

The spinning movement of Earth around its axis is known as Earth's rotation.

The Earth rotates around the Sun in 1 day that is 24 hours but once in every 23 hours, 56 minutes, and 4 seconds with respect to other stars.

According to the Indian astronomer Aryabhata, Earth rotates about its axis daily.

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An 89 kg man drops from rest on a diving board −3.1 m above the surface of the water and comes to rest 0.5 s after reaching the

OLga [1]

To solve this problem we will use the linear motion kinematic equations, for which the change of speed squared with the acceleration and the change of position. The acceleration in this case will be the same given by gravity, so our values would be given as,

$m= 89 kg\\x = 3.1 m\\t = 0.5s\\a = g = 9.8m/s^2$

Through the aforementioned formula we will have to

$v_f^2-v_i^2 = 2ax$

The particulate part of the rest, so the final speed would be

$v_f^2 = 2gx$

$v_f=\sqrt{2(9.8)(3.1)}$

$v_f = 7.79m/s$

Now from Newton's second law we know that

$F = ma$

Here,

m = mass

a = acceleration, which can also be written as a function of velocity and time, then

$F = m\frac{dv}{dt}$

Replacing we have that,

$F = (89)\frac{7.79}{0.5}$

$F = 1386.62N$

Therefore the force that the water exert on the man is 1386.62

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4 years ago

I’m ugly ain’t I ??????

olga55 [171]

Aw don’t say that! I’m sure your beautiful:)

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3 years ago

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Which of the following does culture contribute to the preferences and<br> behaviors of consumers?

faltersainse [42]

Answer:

Values and beliefs

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Dan is 50 years old, is beginning to look back at the successes and failures in his life, and hopes to use this reflection to de

Mice21 [21]

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C. Midlife Crisis.

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3 years ago

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A toy rocket is launched with an initial velocity of 12.0 m/s in the horizontal direction from the roof of a 30.0-m-tall buildin

OlgaM077 [116]

Solution :

The motion in the y direction.

The time taken by the toy rocket to hit the ground,

$S=ut+\frac{1}{2}at^2$

S = distance travelled = 30 m

u = 0 m/s

a = $9.8 \ m/sec^2$

t= time in seconds

Therefore, $30 =\frac{1}{2}9.8 t^2$

t = 2.47 sec

Now motion in the x direction,

u = 12 m/sec

$a=1.6 t \ m/sec^3$

Upon integration 'v' with respect to 't'

$v=\frac{1.6t^2}{2}+12$

Once again integrating with respect to t,

$s=\frac{1.6t^3}{6}+12 t$

$s=\frac{1.6(2.47)^3}{6}+12 (2.47)$

= 0.0176+29.64

= 29.65 m

Therefore, the toy rocket will hit the ground at 29.65 m from the building.

7 0

3 years ago