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kenny6666 [7]
3 years ago
7

Magnetic field lines surrounding a magnet are conventionally drawn

Physics
2 answers:
Lady bird [3.3K]3 years ago
7 0
North to South. Cannot switch around.
satela [25.4K]3 years ago
5 0
B) from north to south
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Calculate a rate of cooling down of air from 80 C to 5C Show calculation. Give an answer in cubic meters per minute and cfm.
antoniya [11.8K]

Explanation:

Given that,

Rate of cooling of air

Initial temperature= 80°C

Final temperature = 5°C

We need to calculate

Using newton's law of cooling

\dfrac{dT}{dt}=c(T-T_{0})

\dfrac{dT}{dt}=c(\dfrac{T_{1}+T_{2}}{2}-T_{0})

Where, dT=T_{1}-T_{2}

Here, T =\dfrac{T_{1}+T_{2}}{2}

T_{0} = 25°C  (surrounding temperature)

dt = 1 minute

\dfrac{dT}{dt}=c(\dfrac{T_{1}+T_{2}}{2}-T_{0})

Put the value into the formula

\dfrac{80-5}{1}=c(\dfrac{85}{2}-25)

c=\dfrac{75}{17.5}

c=4.285\ cubic\ meter/minute

Hence, This is the required answer.

3 0
3 years ago
Help in my home work!<br>convert 80°c to fahrenheit?​
Vsevolod [243]

Answer:

176 degrees fahrenheit

Explanation:

80°C × 9/5) + 32 = 176°F

Mark me brainliest!!

7 0
2 years ago
In just 0.30 s , you compress a spring (spring constant 5000 n/m ), which is initially at its equilibrium length, by 4.0 cm. par
Ierofanga [76]
The average power output is the ratio between the work done to compress the spring, W, and the time taken, t:
P= \frac{W}{t} (1)

The work done is equal to the elastic energy stored by the compressed spring:
W=U= \frac{1}{2}kx^2
where k=5000 N/m is the spring constant and x=4.0 cm=0.04 m is the compression of the spring. If we substitute the numbers, we find:
W= \frac{1}{2}(5000 N/m)(0.04 m)^2=4 J

And now we can use eq.(1) to calculate the average power output:
P= \frac{W}{t}= \frac{4 J}{0.30 s}  =13.3 W
7 0
3 years ago
When describing electromagnetic radiation, there is a(n) _____________ relationship between wavelength and frequency and the gre
ololo11 [35]

Correct option is (C) inverse ; more

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8 0
3 years ago
Read 2 more answers
An electron experiences a downward force of 12.8×10-19 N while traveling in a magnetic field of 8×10-5 T west, what is the magni
SashulF [63]

Answer:

v=10^5\ m/s

Explanation:

Given that,

Magnetic force acting on an electron, F=12.8\times 10^{-19}\ N

The magnitude of the magnetic field,B=8\times 10^{-5}\ T

We need to find the magnitude of the velocity. We know that the magnetic force is given by :

F=qvB

Where

v is the velocity

So,

v=\dfrac{F}{qB}\\\\v=\dfrac{12.8\times 10^{-19}}{1.6\times 10^{-19}\times 8\times 10^{-5}}\\\\v=10^5\ m/s

So, the magnitude of velocity is10^5\ m/s.

4 0
2 years ago
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