How will the motion of a falling whirligig compare to that of a falling paper ball?

Physics

1 answer:

kicyunya [14]2 years ago

4 0

The motion of a falling whirligig is different to that of a falling paper ball due to spinning.

<h3>Type of motion performed by whirligig and falling paper ball </h3>

The motion of a falling whirligig is different from the motion of a falling paper ball because the paper ball falls on the ground without spinning while on the other hand, the whirligig falls on the ground along with spinning.

The falling whirligig performs two motion i.e. one is falling on the ground and the other is spinning during motion whereas paper ball performs one motion i.e. motion in the air towards the ground so we can conclude that the motion of a falling whirligig is different than of a falling paper ball.

Learn more about motion here: brainly.com/question/453639

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Is the refraction different entering medium that has a higher index of refraction compared to entering amedium that has a lower

oee [108]

Answer:

Yes

Explanation:

The speed of light when it travels through glass, diamond, etc, the light travels at different speed from the speed of light. Speed of the light in material is related to the index of refraction.

The change in speed which occurs when the light passes from one medium to the another is responsible for bending of the light which is called as refraction.

When the light goes into a medium with the higher index of the refraction, light bends towards normal. Conversely, if the light traveling goes from higher refractive index to lower refractive index, it will bend away from the normal.

Hence, the refraction is different in both the scenario.

6 0

3 years ago

How long must a tow truck apply a force of 600 N to increase the speed of a 1,500 kg car at rest to 2 m/s?

slega [8]

The time the truck must apply the given force to increase its speed to given value is 5 s.

The given parameters;

applied force, F = 600 N
mass of the truck, m = 1,500 kg
speed of the truck, v = 2 m/s

The force applied to the truck is determined by Newton's second law of motion; which states that the force applied to an object is directly proportional to the product of mass and acceleration of the object.

F = ma

$F = \frac{mv}{t} \\\\t = \frac{mv}{F} \\\\t = \frac{1500 \times 2}{600} \\\\t = 5 \ s$