<span>(x, y)→(x − 8, y − 7) is the correct translation. Take point D for example. The coordinate of D is (2, 5). The coordinate of D' (after translation) is (-6, -2). Since 2-8=-6, 5-7=-2, only the first choice is correct. You can also try other points and see why only this is the right translation.</span>
Answer:
B. No, this distribution does not appear to be normal
Step-by-step explanation:
Hello!
To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.
The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.
As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.
The answer is B.
I hope it helps!
Answer:
(x) = 
Step-by-step explanation:
let y = g(x) and rearrange making x the subject, that is
y = 4x - 11 ( add 11 to both sides )
y + 11 = 4x ( divide both sides by 4 )
= x
Change y back into terms of x , with x =
(x) , thus
(x) = 
The probability that the sample mean is less than 30 school days will be given as follows:
the z-score is given by:
z=(x-μ)/σ
where
μ- stand deviation
σ-mean
thus the z-score of our information is:
z=(30-28)/9
z=0.222222
hence the probability that the sample mean is less than 30 will be:
P(x<30)=0.5871~58.71%