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11Alexandr11 [23.1K]
3 years ago
15

Between 11 P.M. and 8:45 A.M., the water level in a swimming pool decreased by 3/8 in. Assuming that the water level decreased a

t a constant rate, how much did the water level drop each hour?
Mathematics
1 answer:
jeka943 years ago
4 0

Answer:

the water level drop per hour is \frac{1}{26}\,\,\frac{in}{h} \approx 0.03846\,\,\frac{in}{h}

Step-by-step explanation:

Notice that in between 11 PM and 8:45 AM on the following day, there is a change in time equal to 9 hours and 45 minutes = 9.75 hours.

If the water level of the pool dropped by 3/8 of an inch, and the rate was constant, then the rate of level drop per hour is:

\frac{\frac{3}{8} in}{9.75\,h} =\frac{1}{26}\,\,\frac{in}{h} = 0.03846\,\,\frac{in}{h}

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4 years ago
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