Answer:
- <u><em>About 0.22</em></u>
Explanation:
There are two sets:
- Set W of incoming seniors who took AP World History, and
- Set E of incoming seniors who took AP European History
And there is a subset, which is the intersection of those two sets:
- Subset W ∩ E of senior students who took both.
The incoming seniors who are allowed to enroll in AP U.S. History, call them the subset S, is the set of those students that belong to W or E or both W ∩E.
By property of sets:
- S = W + E - W∩E = 175 + 36 - 33 = 178
Then, 178 out of 825 incoming seniors took one or both courses, and the desired probability of a randomly selected incoming senior is allowed to enroll in AP U.S. History is:
Answer:
The explanation is on top x=10
First, find out how much he made in the week total: 24($8.75) = $210
The, find 1.45% of 210: (.0145)(210) = 3.045
*note that 1.45% = .0145*
Round that number to 3.05 and you have your answer
Answer:
x = 4, y = -4
Step-by-step explanation:
9x + 3y = 24
3x + y = 8 divide both sides by 3
y = 8 - 3x subtract 3x from both sides
2y + 4x = 8
2(8 - 3x) + 4x = 8 replace y with 8 - 3x
16 - 6x + 4x = 8 distributive property
-6x + 4x = 8 - 16 subtract 16 from both sides
-2x = -8 divide both sides by -2
x = 4
y = 8 - 3x
y = 8 - 3(4) replace x with 4
y = 8 - 12
y = -4
Answer:
BC = 8
Step-by-step explanation:
AB + BC = AC
4x + 8 + 3x - 4 = 32
7x + 4 = 32
7x = 32 - 4
7x = 28
x = 28/7
x = 4
BC = 3x - 4 = 3*4 - 4 = 12 - 4 = 8
