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tatiyna
3 years ago
13

PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE H

ELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP!!
SUPER EASY CHEMISTRY LONE PAIRS

Chemistry
1 answer:
yulyashka [42]3 years ago
8 0
I’m going to have to stick with true?
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Which would result in radioactive decay? Check all that apply
Gekata [30.6K]

6+2=115 and its good it took test



4 0
3 years ago
Read 2 more answers
For the of freezing liquid ethanol at a given temperature and pressure,A. ΔH is positive and ΔS is positive.B. ΔH is positive an
Ksivusya [100]

Answer:

ΔH is negative and ΔS is negative.

Explanation:

Endothermic reaction -

The type of reaction in which energy is absorbed in the form of heat is known as endothermic reaction .

The reaction mixture usually get cooled after the reaction .( temperature decreases ) .

The sign of ΔH of an Endothermic  reaction is positive .

<u>For the of process of freezing the liquid ethanol  ,  energy in the form of heat is released and hence , exothermic reaction ΔH is negative  .</u>

<u>In the process of freezing , liquid is converted to solid , i.e. , the randomness reduces , and hence , entropy also decreases , hence , ΔS is negative .</u>

3 0
3 years ago
WILLL GIVE BRAINLIEST IF YOU ANSWERRR PLEASEEEE IM LITERALLY BEGGING YOU I PUT THIS QUESTION IN SOO MANY TIMES I HAVEN'T GOTTEN
tino4ka555 [31]

Answer:

The answer is 375.54 g of AgBr

Explanation:

Mass (g) = Concentration (mol/L) x volume (L) x Molecular Weight of AgBr (g/mol)

Mass = 2M x 1L x 187.77 g/mol

Mass = 375.54g

6 0
2 years ago
During beta decay, a nucleus _________.. a. gains a proton and loses a neutron. b. gives up two protons and two neutrons. c. mai
Alexxandr [17]
Hello!

<span>a. gains a proton and loses a neutron. </span>This process gives more stability to the atom.

Hugs!
8 0
3 years ago
What is the value of the equilibrium constant, K, for a reaction for which ∆G° is equal to –5.20 kJ at 50°C?
frutty [35]

Answer:

6.93

Explanation:

Step 1: Given data

  • Standard Gibbs free energy (∆G°): -5.20 kJ
  • Temperature (T): 50°C
  • Equilibrium constant (K): ?

Step 2: Convert the temperature to the Kelvin scale

We will use the following expression.

K = °C + 273.15

K = 50°C + 273.15

K = 323 K

Step 3: Calculate K

We will use the following expression.

∆G° = -R × T × ln K

-5.20 × 10³ J = -(8.314 J/mol.K) × 323 K × ln K

K = 6.93

5 0
3 years ago
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