Answer:
ΔT = 1,41°C
Explanation:
For the reaction:
2HCl(aq) + Ba(OH)₂(aq) → BaCl₂(aq) + 2 H₂O(l); ΔH = –118 kJ.
If moles of reaction are:
HCl:
0,0500L×0,20M = 0,01moles
Ba(OH)₂:
0,0500L×0,10M = 0,005moles
The heat produced is:
0,005mol×-118 kJ/mol = -0,59 kJ = -590 J
The temperature increasing is:
Q = -C×m×ΔT
Where Q is heat (-590 J), m is mass of solution (100mL = 100g -density of 1,00g/mL) and ΔT is change in temperature.
Replacing:
-590J = -4,184J/g°C×100g×ΔT
<em>ΔT = 1,41°C</em>
<em></em>
I hope it helps!
The distance from the nucleus is close to the electron orbital of the earth
It is important to determine the qcalorimeter before determining the qmetal because the qcalorimeter is a constant and it's value is used to find the value of qmetal.
The option, B. Reduced friction means reduced heat transfer " is correct.
