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In-s [12.5K]
4 years ago
5

Why is it important to determine the qcalorimeter before determining the qmetal??

Chemistry
2 answers:
Dmitry [639]4 years ago
6 0

In order to determine the heat absorbed or given by a metal it is important to determine the heat loss or gained by calorimeter

If we dip a hot metal piece in a calorimeter, it will lose energy which will be absorbed by calorimeter

The heat absorbed by calorimeter = heat loss by metal

the heat absorbed by calorimeter = heat capacity of calorimter X change in temperature

so we should have the value of heat absorbed by calorimeter which will be equal to the heat loss by metal

heat loss by metal = mass of metal X specific heat of metal X change in temperature

thus we can calculate the specific heat of metal.

svet-max [94.6K]4 years ago
5 0
It is important to determine the qcalorimeter before determining the qmetal because the qcalorimeter is a constant and it's value is used to find the value of qmetal.
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Name three stars that are hotter than the sun
devlian [24]

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4 years ago
I WILL GIVE YOU BRAINLYEST AND 100 POINTS PLSSSS HELP
shutvik [7]

Answer:

Each element has unique physical properties such as density, melting point, boiling point, etc. These properties can be used to identify an element using a reference book that contains such information about each element. Flame tests, atomic spectra, and spectroscopy can be used to identify some elements.

Explanation:

7 0
3 years ago
Balance the following equation on scrap paper:<br> AIF3+Li2O → Al2O3 + LiF
Oxana [17]

Answer:

2AlF₃ + 3Li₂O —> Al₂O₃ + 6LiF

Explanation:

AlF₃ + Li₂O —> Al₂O₃ + LiF

The above equation can be balanced as follow:

AlF₃ + Li₂O —> Al₂O₃ + LiF

There are 2 atoms of Al on the right side and 1 atom on the left side. It can be balance by writing 2 before AlF₃ as shown below:

2AlF₃ + Li₂O —> Al₂O₃ + LiF

There are 6 atoms of F on the left side and 1 atom on the right side. It can be balance by writing 6 before LiF as shown below:

2AlF₃ + Li₂O —> Al₂O₃ + 6LiF

There are 2 atoms of Li on the left side and 6 atoms on the right side. It can be balance by writing 3 before Li₂O as shown below:

2AlF₃ + 3Li₂O —> Al₂O₃ + 6LiF

Thus, the equation is balanced..!

8 0
3 years ago
Heat is added to a chemical system. Which energy will increase?
dmitriy555 [2]

Answer:

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Explanation: i hope this is the correct answer if this is wrong or incorrect please let me know

8 0
3 years ago
Read 2 more answers
In this lab, you are to carry out the formation of a Grignard reagent from 1-bromo-benzene andits subsequent reaction with solid
yan [13]

Answer:

(A). C6H5Br + Mg(in ether) -----------> C6H5MgBr.

(B). C6H5MgBr + O = C = O -----------> C6H5-COO^- Mg^+ Br.

(C). C6H5-COO^- Mg^+ Br + HCl --------> C6H5-COOH + Mg^+Br(OH).

PRODUCTS=> C6H5-COOH and Mg^+Br(OH).

Explanation:

A Grignard reagent is a reagent that/which is an organometallic compound that is R -Mg- X. The R = alkyl, vinyl or allyl and the X = halogens.

It must be noted that an important reaction of Grignard reagent is its reaction with compounds containing the Carbonyl that is -CO functional group and this kind of Reaction is known as a Grignard Reaction.

So, in this question we are told that;

=> "1-bromo-benzene andits subsequent reaction with solid carbon dioxide (CO2) followed by acidic workup (using HCl asthe acid). "

Thus;

(A). C6H5Br + Mg(in ether) -----------> C6H5MgBr.

(B). C6H5MgBr + O = C = O -----------> C6H5-COO^- Mg^+ Br.

(C). C6H5-COO^- Mg^+ Br + HCl --------> C6H5-COOH + Mg^+Br(OH).

5 0
4 years ago
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