Answer:
b) [Kr] 5s² 4d¹⁰ 5p⁵
Explanation:
Properties of iodine:
Iodine is present in group seventeen.
It is halogen element.
Its atomic mass is 127 amu.
Its atomic number is 53.
It is present in solid form.
It is crystalline in nature.
It is very corrosive and has pungent odor.
It can not react with oxygen and nitrogen.
Electronic configuration:
I₅₅ = 1s² 2s² 2p⁶ 3s³ 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁵
Abbreviated electronic configuration:
I₅₅ = [Kr] 5s² 4d¹⁰ 5p⁵
Abbreviated electronic configuration is shortest electronic configuration by using the noble gases.
The four states of matter are solid, liquid, gas, and plasma.
Solid: a solid object has a definite volume and shape i.e. A box
Liquid: liquid has a definite volume but no definite shape i.e. Water
Plasma: plasma has some of the properties of gas but it's a good trainer of electricity and is a affected in a magnetic field i.e. A star
Gas: gas does not have a definite shape or volume so it takes the shoe of its container i.e. Balloon
Answer: Francesco Redis Experiment part 1 : The maggots were not observed in setup B and setup C because the jars were covered.
part 2 : He discovered that maggots appeared on the meat in the control jar, the jar left open. No maggots appeared in the jar covered with gauze.
Pasteur Experiment
part 1:In the pastures Experiment the microorganisms come from the air.
part 2:Louis Pasteur's pasteurization experiment illustrates the fact that the spoilage of liquid was caused by particles in the air rather than the air itself.
Explanation:
Answer:
Explanation:
Hello,
In this case, for the given reaction at equilibrium:
We can write the law of mass action as:
![Keq=\frac{[CH_3OH]}{[CO][H_2]^2}](https://tex.z-dn.net/?f=Keq%3D%5Cfrac%7B%5BCH_3OH%5D%7D%7B%5BCO%5D%5BH_2%5D%5E2%7D)
That in terms of the change 
due to the reaction extent we can write:
![Keq=\frac{x}{([CO]_0-x)([H_2]_0-2x)^2}](https://tex.z-dn.net/?f=Keq%3D%5Cfrac%7Bx%7D%7B%28%5BCO%5D_0-x%29%28%5BH_2%5D_0-2x%29%5E2%7D)
Nevertheless, for the carbon monoxide, we can directly compute as shown below:
![[CO]_0=\frac{0.45mol}{1.00L}=0.45M\\](https://tex.z-dn.net/?f=%5BCO%5D_0%3D%5Cfrac%7B0.45mol%7D%7B1.00L%7D%3D0.45M%5C%5C)
![[H_2]_0=\frac{0.57mol}{1.00L}=0.57M\\](https://tex.z-dn.net/?f=%5BH_2%5D_0%3D%5Cfrac%7B0.57mol%7D%7B1.00L%7D%3D0.57M%5C%5C)
![[CO]_{eq}=\frac{0.28mol}{1.00L}=0.28M\\](https://tex.z-dn.net/?f=%5BCO%5D_%7Beq%7D%3D%5Cfrac%7B0.28mol%7D%7B1.00L%7D%3D0.28M%5C%5C)
![x=[CO]_0-[CO]_{eq}=0.45M-0.28M=0.17M](https://tex.z-dn.net/?f=x%3D%5BCO%5D_0-%5BCO%5D_%7Beq%7D%3D0.45M-0.28M%3D0.17M)
Finally, we can compute the equilibrium constant:
Best regards.
