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olga55 [171]
3 years ago
9

Which statement would be a valid argument in favor of using nuclear power? There are few negative impacts from mining the fuel.

Reactors are safe from natural disasters. There are little to no waste products from fission. Nuclear power does not contribute greenhouse gases.
Physics
2 answers:
fgiga [73]3 years ago
6 0
Okay so, lets use the process of elimination here. 

<span>A)There are few negative impacts from mining the fuel.
B)Reactors are safe from natural disasters.
C)There are little to no waste products from fission.
D)Nuclear power does not contribute greenhouse gases.

First off, we know B cannot be correct, seeing as how reactors are fragile and are damaged easily by Japan's earthquakes. So we can eliminate B from the choices. We then can eliminate C, since fission creates high levels of nuclear waste, so that leaves us with just A, and D. We can then eliminate A since uranium is radioactive, there is always a chance for negative effects.

So, the correct answer is D</span>
laiz [17]3 years ago
5 0
The answer is D. Nuclear power does not contribute greenhouse gasses
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If some electrons are transferred from object A to object B,
Igoryamba

Answer: A. Object A will have a positive charge.

Explanation: If the number of protons and electrons are the same, their net charges cancel each other out, and you have a neutral charge. If electrons are transferred to another object, the amount of positive charge will outweigh the amount of negative charge. As a result, you are left with an overall positive charge in object A. Meanwhile, object B is now negative.

6 0
3 years ago
if a bullet fired beneath the water, straight up, breaks through the surface at a speed of 25m/s, how high will the bullet be af
Doss [256]

Answer:

32 m and -2.4 m/s

Explanation:

Given:

v₀ = 25 m/s

t = 2.8 s

a = -9.8 m/s²

Find: Δy, v

Δy = v₀ t + ½ at²

Δy = (25 m/s) (2.8 s) + ½ (-9.8 m/s²) (2.8 s)²

Δy = 31.6 m

v = at + v₀

v = (-9.8 m/s²) (2.8 s) + 25 m/s

v = -2.44 m/s

Rounded to two significant figures, the bullet reaches a height of 32 m and a velocity of -2.4 m/s.

8 0
4 years ago
Two electronics technicians are discussing conductors and insulators. Technician A says that conductors have more free electrons
vitfil [10]

Technician A is Correct.

You can see this when he says that conductors have more free electrons than insulators. This statement is True.

While Technician B says that, insulators have the lower resistance than conductors. This statement is False.

4 0
3 years ago
Read 2 more answers
An air bubble at the bottom of a lake 36.0 m deep has a volume of 1.22 cm^3. If the temperature at the bottom is 5.9°C and at th
AlexFokin [52]

Answer:

volume of the bubble just before it reaches the surface is 5.71 cm³

Explanation:

given data

depth h = 36 m

volume v2 = 1.22 cm³ = 1.22 × 10^{-6} m³

temperature bottom t2 = 5.9°C = 278.9 K

temperature top  t1 = 16.0°C = 289 K

to find out

what is the volume of the bubble just before it reaches the surface

solution

we know at top atmospheric pressure is about P1 = 10^{5} Pa

so pressure at bottom P2 = pressure at top + ρ×g×h

here ρ is density and h is height and g is 9.8 m/s²

so

pressure at bottom P2 = 10^{5} + 1000 × 9.8 ×36

pressure at bottom P2 =4.52 × 10^{5}  Pa

so from gas law

\frac{P1*V1}{t1} = \frac{P2*V2}{t2}

here p is pressure and v is volume and t is temperature

so put here value and find v1

\frac{10^{5}*V1}{289} = \frac{4.52*10^{5}*1.22}{278.9}

V1 = 5.71 cm³

volume of the bubble just before it reaches the surface is 5.71 cm³

6 0
3 years ago
Recall that weight is a force and is equal to m*g, where g is the acceleration due to gravity exerted by the Earth near the Eart
Marysya12 [62]

Answer:

145.43 N

Explanation:

Weight is given by (mg)

where m = mass of the body

g = acceleration due to gravity

mass is constant everywhere and is equal to 77.1 kg, both on the earth and on the moon.

But the acceleration due to gravity exerted by the moon near the moon's surface is 16.6% that of Earth,

g(moon) = 0.166 g(earth) = 0.166 × 9.8 = 1.6268 m/s²

Weight on the moon = mg(moon) = (77.1×1.6268) = 125.43 N

3 0
3 years ago
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