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ASHA 777 [7]
3 years ago
9

Which physical property refers to the temperature at which a substance in a solid-state transforms to a liquid state?

Physics
2 answers:
zubka84 [21]3 years ago
5 0
<h2>The answer is C. Melsting point </h2><h3 /><h3>Explanation: The melting point of a substance is the temperature at which substance transforms from a solid state into a liquid state.</h3>
solmaris [256]3 years ago
3 0

Answer:

C: Melting point

Explanation:

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Explain how we as humans can cause multiple problems in the food chain of the ocean
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We might kill too many animals and mess up the food chain because some bigger fish won't be able to eat smaller fish and some smaller fish might not have any organisms to eat.
6 0
3 years ago
Electric pressure is measured is a, current .b,volts,c, Walt's,d, Ampere,e, force​
kolbaska11 [484]

。☆✼★ ━━━━━━━━━━━━━━  ☾

The correct option would be B. volts

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5 0
4 years ago
10. A triply ionized beryllium atom is in the ground state. It absorbs energy and makes a transition to the n = 5 excited state.
Xelga [282]

Answer:

\lambda=1282\ nm

Explanation:

E_n=-2.179\times 10^{-18}\times \frac{1}{n^2}\ Joules

For transitions:

Energy\ Difference,\ \Delta E= E_f-E_i =-2.179\times 10^{-18}(\frac{1}{n_f^2}-\frac{1}{n_i^2})\ J=2.179\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J

\Delta E=2.179\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J

Also, \Delta E=\frac {h\times c}{\lambda}

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

So,  

\frac {h\times c}{\lambda}=2.179\times 10^{-18}(|\frac{1}{n_i^2} - \dfrac{1}{n_f^2}|)\ J

\lambda=\frac {6.626\times 10^{-34}\times 3\times 10^8}{{2.179\times 10^{-18}}\times (|\frac{1}{n_i^2} - \dfrac{1}{n_f^2}|)}\ m

So,  

\lambda=\frac {6.626\times 10^{-34}\times 3\times 10^8}{{2.179\times 10^{-18}}\times (|\frac{1}{n_i^2} - \dfrac{1}{n_f^2}|)}\ m

Given, n_i=5\ and\ n_f=3

\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{{2.179\times 10^{-18}}\times (\frac{1}{5^2} - \dfrac{1}{3^2})}\ m

\lambda=\frac{10^{-26}\times \:19.878}{10^{-18}\times \:2.179\left(|\frac{1}{25}-\frac{1}{9}\right)|}\ m

\lambda=\frac{19.878}{10^8\times \:2.179\left(|-\frac{16}{225}\right|)}\ m

\lambda= 1.2828\times10^{-6}

1 m = 10⁻⁹ nm

\lambda=1282\ nm

6 0
3 years ago
N an experiment, researchers want to determine if the __________ variable causes changes in the __________ variable.
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C

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4 years ago
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