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ASHA 777 [7]
2 years ago
9

Which physical property refers to the temperature at which a substance in a solid-state transforms to a liquid state?

Physics
2 answers:
zubka84 [21]2 years ago
5 0
<h2>The answer is C. Melsting point </h2><h3 /><h3>Explanation: The melting point of a substance is the temperature at which substance transforms from a solid state into a liquid state.</h3>
solmaris [256]2 years ago
3 0

Answer:

C: Melting point

Explanation:

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The largest transition metal is copernicium with 112 protons.
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3 years ago
Bambi the young dear was distracted Buy butterfly and jumped into the road in front of the two vehicles as shown in the diagram
bagirrra123 [75]

Speed of car A is given as

v_a = 70 mph

now we need to convert it into SI units

1 miles = 1609 m

1 hour = 3600 s

now we have

v_a = 70 *\frac{1609}{3600} = 31.3 m/s

now its distance from Bambi is given as

d_a = 350 m

time taken by it to hit the Bambi

t = \frac{d}{v}

t = \frac{350}{31.3}

t = 11.2 s

Now other car is moving at speed 50 mph

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v_b = 50* \frac{1609}{3600}

v_b = 22.35 m/s

now its distance from Bambi is given as

d_b = 590 feet

as we know that 1 feet = 0.3048 m

d_b = 590*0.3048 = 179.83 m

now the time to hit the other car is

t_2 = \frac{179.83}{22.35}

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7 0
3 years ago
Ksp for agbr is 5x10-13. what is the maximum concentration of silver ion that you can have in a 0.1 m solution of nabr?
liberstina [14]

Answer : The maximum concentration of silver ion is 5\times 10^{-12}m

Solution : Given,

K_{sp} for AgBr = 5\times 10^{-13}

Concentration of NaBr solution = 0.1 m

The equilibrium reaction for NaBr solution is,

NaBr(aq)\rightleftharpoons Na^++Br^-

The concentration of NaBr solution is 0.1 m that means,

[Na^+]=[Br^-]=0.1m

The equilibrium reaction for AgBr is,

                          AgBr\rightleftharpoons Ag^++Br^-

At equilibrium                     s       s

The expression for solubility product constant for AgBr is,

K_{sp}=[Ag^+][Br^-]

The concentration of Ag^+ = s

The concentration of Br^- = 0.1 + s

Now put all the given values in K_{sp} expression, we get

5\times 10^{-13}=(s)(0.1+s)

By rearranging the terms, we get the value of 's'

s=5\times 10^{-12}m

Therefore, the maximum concentration of silver ion is 5\times 10^{-12}m.

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3 years ago
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In the absence of air resistance the result is D .
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According to the principal of wave refraction, when light from the atmosphere enters a medium of greater density at an oblique a
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