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Harrizon [31]
3 years ago
9

The orbital velocity of the Earth about the sun is 30 km/s. If the Earth were suddenly stopped in its tracks, it would simply fa

ll radially into the sun. Devise a plan whereby a rocket loaded with radioactive wastes could be fired into the sun for permanent disposal. How fast and in what direction with respect to the Earth's orbit should the rocket be fired?
Physics
1 answer:
soldi70 [24.7K]3 years ago
4 0

Answer:

Planet will crash on to the Sun if the tangential velocity becomes zero and Rocket should be fired  from Earth's orbit is at 30 m/s and in opposite direction to the Earth orbits the Sun

Explanation:

The orbital velocity of the Earth about the sun is 30 km/s. If we shoot a rocket with 30 km/s with respect to Earth in the opposite direction.  Then the two velocity vectors cancel. The resultant velocity would be zero with respect to the Sun. resulting velocity is called as tangential velocity.

Planet will crash on to the Sun if the tangential velocity becomes zero and Rocket should be fired  from Earth's orbit is at 30 m/s and in opposite direction to the Earth orbits the Sun

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You drop a ball from a height of 2.0 m, and it bounces back to a height of 1.5 m. (a) what fraction of its initial energy is los
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a) At a position of 2.0m, the Initial energy is all made up of the potential energy=m*g*hi<span>
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The percentage of energy remaining is E=m*g*hi/m*g*hf x 100 

and since mass and gravity are constant so it leaves us with just E=hi/hf 
which 1.5/2.0 x100= 75% so we see that we lost 25% of the energy or 0.25 in fraction 

b) Here use the equation vf^2=vi^2+2gd 

<span>where g is gravity, vf is the final velocity and vi is the initial velocity while d is the distance travelled

so in here we are looking for the vi so let us isolate that variable 
we know that at maximum height or peak, the velocity is 0 so vf is 0 

therefore,</span></span>

vi =sqrt(-2gd) <span>
vi =sqrt(-2x-9.81x1.5) </span>
<span>vi =5.4 m/s

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3 years ago
B. Assuming the acceleration is still -9.81 m/s2, what is the instantaneous velocity of the
goblinko [34]

We have that the instantaneous velocity of the shuttlecock when it hits the ground is

V_{int}=\sqrt{U^2+19.6H}

From the question we are told

Assuming the acceleration is still -9.81 m/s2, what is the instantaneous velocity of the

shuttlecock when it hits the ground? Show your work below.

Generally the equation for acceleration  is mathematically given as

a=v \frac{dv}{dx}\\\\\Therefore\\\\\2ah=v^2-u^2

Where

acceleration is still -9.81 m/s2,

Hence,

V^2-U^2=2(-9.81)*-H

Therefore

V_{int}=\sqrt{U^2+19.6H}

For more information on this visit

brainly.com/question/12319416?referrer=searchResults

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