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Harrizon [31]
3 years ago
9

The orbital velocity of the Earth about the sun is 30 km/s. If the Earth were suddenly stopped in its tracks, it would simply fa

ll radially into the sun. Devise a plan whereby a rocket loaded with radioactive wastes could be fired into the sun for permanent disposal. How fast and in what direction with respect to the Earth's orbit should the rocket be fired?
Physics
1 answer:
soldi70 [24.7K]3 years ago
4 0

Answer:

Planet will crash on to the Sun if the tangential velocity becomes zero and Rocket should be fired  from Earth's orbit is at 30 m/s and in opposite direction to the Earth orbits the Sun

Explanation:

The orbital velocity of the Earth about the sun is 30 km/s. If we shoot a rocket with 30 km/s with respect to Earth in the opposite direction.  Then the two velocity vectors cancel. The resultant velocity would be zero with respect to the Sun. resulting velocity is called as tangential velocity.

Planet will crash on to the Sun if the tangential velocity becomes zero and Rocket should be fired  from Earth's orbit is at 30 m/s and in opposite direction to the Earth orbits the Sun

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Answer:

(a) 108

(b) 110.500 kW

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Solution:

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Voltage at primary, V_{p} = 120\ V          (rms voltage)

Voltage at secondary, V_{s} = 13000\ V  (rms voltage)

Current in the secondary, I_{s} = 8.50\ mA  

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(a) The ratio of secondary to primary turns is given by the relation:

\frac{N_{s}}{N_{p}} = \frac{V_{s}}{V_{s}}

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N_{p} = No. of turns in primary

N_{s} = No. of turns in secondary

\frac{N_{s}}{N_{p}} = \frac{13000}{120} ≈ 108

(b) The power supplied to the line is given by:

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(c) The current rating that the fuse should have is given by:

\frac{V_{s}}{V_{p}} = \frac{I_{p}}{I_{s}}

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