Answer:
The speed of the car is 20.84 m/s.
Explanation:
Given that,
The distance covered by the car, d = 150 km
Time, t = 7200 s
We need to find the speed of the car. We know that the speed of an object is given by total distance divided by total time taken. Mathematically,
So, the speed of the car is 20.84 m/s.
Answer:
So logically speaking the question you have asked makes no sense
Explanation:
Zero what? After landing where? How what? before asking a question think about how other people will read it.
Answer:
θ = 26.6°
Explanation:
Formula for maximum height is;
h = u²sin²θ/2g
We are told maximum height is 25 m, thus;
u²sin²θ/2g = 25 - - - - (eq 1)
Formula for horizontal range is;
R = u²sin2θ/g
In Mathematics, sin2θ = 2sinθcosθ
So; R = 2u²sinθcosθ/g
R = 2u²sinθcosθ/g
We are given Horizontal range = 200 m.
Thus;
2u²sinθcosθ/g = 200 - - - - (eq 2)
Divide eq 1 by eq 2 to get;
200/25 = 4cosθ/sinθ
8 = 4cosθ/sinθ
4/8 = sinθ/cosθ
0.5 = tan θ
θ = tan^(-1) 0.5
θ = 26.6°
Answer:
R = 103.7 N, 31.6° above x-axis
Explanation:
First we find the x components of all the forces:
F1x = F1 Cos 60°
F1x = (100 N)(Cos 60°)
F1x = 50 N
F2x = F2 Cos 140°
F2x = (200 N)(Cos 140°)
F2x = -153.2 N
F3x = F3 Cos 320°
F3x = (250 N)(Cos 320°)
F3x = 191.5 N
So, the x component of resultant will be the sum of the x component of each force:
Rx = F1x + F2x + F3x
Rx = 50 N - 153.2 N + 191.5 N
Rx = 88.3 N
Now we find the y components of all the forces:
F1y = F1 Sin 60°
F1y = (100 N)(Sin 60°)
F1y = 86.6 N
F2y = F2 Sin 140°
F2y = (200 N)(Sin 140°)
F2y = 128.5 N
F3y = F3 Sin 320°
F3y = (250 N)(Sin 320°)
F3y = -160.7 N
So, the y component of resultant will be the sum of the y component of each force:
Ry = F1y + F2y + F3y
Ry = 86.6 N + 128.5 N - 160.7 N
Ry = 54.4 N
Hence, the magnitude of resultant force will be:
|R| = √(Rx² + Ry²)
|R| = √[(88.3 N)² + (54.4 N)²]
|R| = √10756.25 N²
|R| = 103.7 N
And the direction θ will be:
θ = tan⁻¹(Ry/Rx)
θ = tan⁻¹(54.4/88.3)
θ = 31.6° above x-axis
Hence, the resultant vector will be:
<u>R = 103.7 N, 31.6° above x-axis</u>