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sukhopar [10]
3 years ago
7

Which of these geometric figures can intersect to form a cross section? Check all that apply. 1.a line and a prism 2.a line and

a rectangle 3.a point and a prism 4.a prism and a horizontal plane 5.a vertical plane and a pyramid        Check all that apply

Mathematics
2 answers:
stira [4]3 years ago
6 0

Answer:

4 and 5

Step-by-step explanation:

LiRa [457]3 years ago
5 0
<span>A cross section is formed by the <em>intersection</em> of a<em> three-dimensional object</em> and a <em>plane.</em>

So the right answers are 4 and 5.

Let's explain each case.

First. A prism and a horizontal plane

The representation of this statement is shown in Figure 1. A prism has the following characteristics:

1. These objects have identical ends.
2. They have flat faces.
3. They have </span><span>the same </span>cross section<span> all along its length </span><span>

So in the figure, you can see how the horizontal plane intersects the prism. <em>The cross section</em> of this object <em>is a</em> <em>triangle</em>. Thus, </span><span>it has the same cross section all along its length and this object is called <em>a triangular prism.</em></span><span>

Second. A vertical plane and a pyramid

As shown in Figure 2 you can see the representation of this statement. </span><span>If the pyramid is cut with a plane that passes through the top vertex and it is perpendicular to the base, then the intersection of this pyramid and the plane becomes a <em>triangular cross section</em>.</span>

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Sloan [31]

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Given :

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replace x with x+h

f(x) = x^2 - 7x + 8 \\f(x+h)=\mathrm{ }\left(x+h\right)^2-7\left(x+h\right)+8\\Expand \; and \; simplify\\f(x+h)=x^2+2xh+h^2-7\left(x+h\right)+8\\f(x+h)=x^2+2xh+h^2-7x-7h+8

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Learn more :brainly.com/question/23630564

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