What is the maximum volume of a 0.788 M CaCl2 solution that can be prepared using 85.3 g CaCl2?

1 answer:

5 0

Molar mass CaCl₂ = 110.98 g/mol

Number of moles:

1 mole CaCl₂ ---------> 110.98 g
n mole CaCl2 ---------> 85.3 g

n = 85.3 / 110.98

n = 0.7686 moles of CaCl₂

Volume = ?

M = n / V

0.788 = 0.7686 / V

V = 0.7686 / 0.788

V = 0.975 L

hope this helps!

You might be interested in

Which of the following are characteristics of vertebrates?

djverab [1.8K]

Answer:
All of the above

Explanation:
Vertebrates are a class of creatures falling under kingdom "Animalia" that are characterized by the presence of an internal skeleton composed of bones.

Vertebrates are characterized by the following:
1- presence of internal skeleton
2- developed brain
3- the presence of an advanced nervous system connected to the brain
4- presence of muscles that allow movement
5- protective skin
6- circulation of blood in the bodies in the vessels

Comparing the mentioned characteristics with the options given, we will find that the most suitable answer is: "all of the above".

Hope this helps :)

5 0

3 years ago

Read 2 more answers

2NOCl(g) ↔ 2NO(g) + Cl2(g) with K = 1.6 x10–5. In an experiment, 1.00 mole of pure NOCl and 1.00 mole of pure Cl2 are placed in

poizon [28]

Answer: $3.8\times 10^{-3}M$