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Naily [24]
3 years ago
13

A solution containing a mixture of metal cations was treated with dilute HCl and no precipitate formed. Next, H2S was bubbled th

rough the acidic solution. A precipitate formed and was filtered off. Then, the pH was raised to about 8 and H2S was again bubbled through the solution. A precipitate again formed and was filtered off. Finally, the solution was treated with a sodium carbonate solution, which resulted in no precipitation. Which metal ions were definately present, which were definitely absent, and which may or may not have been present in the original mixture?Ag+, Ba2+, Mg2+, Hg2+, Pb2+, Hg2^2+, Cu2+, Zn2+, Ni2+, Co2+, Sn2+, Li+, Sb3+
Chemistry
1 answer:
erica [24]3 years ago
5 0

Answer:

Explanation:

  Ions which will  be definitely  absent -

Ag⁺ , Hg₂⁺ , Pb⁺², because their chlorides are insoluble in water.

Ba⁺² ,Ca⁺² because their carbonates are insoluble in water,

Ions which will be definitely present  

Cu⁺² , Pb⁺² . Hg⁺² , Sb⁺³ , Sn⁺² , because their sulphides are insoluble at pH = 8.

For the rest nothing can be said.

 

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The condition of acidosis can also cause ____________ because the higher H concentration diffuses to the ICF, pushing K towards
Rina8888 [55]

Answer:

Hyperkalemia

Explanation:

The condition of acidosis can also cause Hyperkalemia because the higher H concentration diffuses to the ICF, pushing K towards the ECF.

4 0
2 years ago
If an atom contains one electron and one proton,will it carry any charge or not​
sertanlavr [38]

Answer:

no it will have no charge...it would be electrically neutral! because the number of protons and electrons are equal!

8 0
3 years ago
Read 2 more answers
How many moles are in 9.25E24 formulas units of sodium acetate?
Lelu [443]

Answer:

<h2>15.37 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{9.25 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 15.365448...

We have the final answer as

<h3>15.37 moles</h3>

Hope this helps you

5 0
3 years ago
Calculate the percent ionic, the percent covalent, and the bond length (in picometers) of a chemical bond between phosphorus and
kirza4 [7]

Answer:

The correct option is;

4 percent ionic, 96 percent covalent, 222 pm

Explanation:

The parameters given are;

Phosphorus:

Atomic radius = 109 pm

Covalent radius = 106 pm

Ionic radius = 212 pm

Electronegativity of phosphorus = 2.19  

Selenium:

Atomic radius = 122 pm

Covalent radius = 116 pm

Ionic radius = 198 pm

Electronegativity of selenium= 2.55  

The percentage ionic character of the chemical bond between phosphorus and selenium is given by the relation;

Using Pauling's alternative electronegativity difference method, we have;

\% \, Ionic \ Character = \left [18\times (\bigtriangleup E.N.)^{1.4}  \right ] \%

Where:

Δ E.N. = Change in electronegativity = 2.55 - 2.19 = 0.36

Therefore;

\% \, Ionic \ Character = \left [18\times (0.36)^{1.4}  \right ] \% = 4.3 \%

Hence the percentage ionic character = 4.3% ≈ 4%

the percentage covalent character = (100 - 4.3)% = 95.7% ≈ 96%

The bond length for the covalent bond is found adding the covalent radii of both atoms as follows;

The bond length for the covalent bond = 106 pm + 116 pm = 222 pm.

The correct option is therefore, 4 percent ionic, 96 percent covalent, 222 pm.

4 0
3 years ago
I need it done assapp
Alja [10]

Answer:

water molecules

Explanation:

4 0
3 years ago
Read 2 more answers
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