3 years ago

Real world problem for 3x-15=10

1 answer:

3 0

A group of men have x dollars each, then they all want to buy something that costs $15 dollars, they group their money and pay up, then they have $10 left, how much did each man start with?

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(-5x^6+7x+1)-(8x^2+x-10)<br><br> Algebra 1 subtracting polynomials please help

BaLLatris [955]

Answer:

-5x^6-8x^2+6x+11

Step-by-step explanation:

(-5x^6+7x+1)-(8x^2+x-10)

Remove parentheses

-5x^6+7x+1-(8x^2+x-10)

-(8x^2+x-10)=-8x^2-x+10

-5x^6+7x+1-8x^2-x+10

Simplify

-5x^6-8x^2+6x+11

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3 years ago

How to divide 8 by 3 the long way

PilotLPTM [1.2K]

The number 8 divided by 3 is 2 with a remainder of 2 (8 / 3 = 2 R.

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3 years ago

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If you make $8 an hour and you get a 10% raise how much are you making now

alexira [117]

Answer:

$8.8

Step-by-step explanation:

$8*0.10=0.8$

$8+0.8=8.8$

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3 years ago

If f(x)=x^2- 4 and g(x)=x^2 plus 2 x,

gregori [183]

Answer:

$\huge\boxed{(f-g)\left(-\dfrac{1}{3}\right)=-3\dfrac{1}{3}}$

Step-by-step explanation:

$\text{We have}:\\\\f(x)=x^2-4\ \text{and}\ g(x)=x^2+2x\\\\(f-g)(x)=f(x)-g(x)\\\\\text{therefore}\\\\(f-g)(x)=(x^2-4)-(x^2+2x)=x^2-4-x^2-2x\\\\=(x^2-x^2)-2x-4=-2x-4\\\\(f-g)\left(-\dfrac{1}{3}\right)\to\text{put}\ x=-\dfrac{1}{3}\ \text{to the equation of the function}\ (f-g)(x):\\\\(f-g)\left(-\dfrac{1}{3}\right)=-2\left(-\dfrac{1}{3}\right)-4=\dfrac{2}{3}-4=-3\dfrac{1}{3}$

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4 years ago

What digit could be in the ten millions place of a number that is greater than 25 million but less than 73 million

irga5000 [103]

26-72 million because It has to be greater than 25 and less than 73 so you you a number in between

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4 years ago