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Maksim231197 [3]
3 years ago
11

A buffer is formed by mixing 100 ml of 0.1 m nh4cl with 50 ml of 0.3 m nh3. to this solution 13 ml of 0.1 m naoh is added. what

is the approximate ph of the new solution after neutralization? assume a kb of 1.8 × 10−5 for the weak base. 1. 4.62 2. 4.47 3. 9.38 4. 9.45 5. 9.53
Chemistry
1 answer:
Hoochie [10]3 years ago
8 0
I had the same question last week and my answer was C. Try that.
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Please inbox me I will thanks your all answers​
prohojiy [21]

Answer:

Really

Explanation:

3 0
3 years ago
H2CO3(aq) → CO2(aq) + H2O(l) After strenuous exercise, you breathe heavily, exhaling and removing CO2 from your body. The remova
Aleksandr-060686 [28]

Answer:

did you find the answer

Explanation:

help

6 0
2 years ago
The amount of heat absorbed when 5.5g of aluminum is heated from 25.0c to 95.0c the specific heat of aluminum is 0.897J/(gc)​
NemiM [27]

Answer:

Q=21.99 kJ

Explanation:

4 0
3 years ago
I NEED THE ANSWER IMMEDIATELY TONIGHT, PLEASE!!!
anzhelika [568]

Answer:

Ra,Ba,In,Sb,As,P hope this helps you out good luck

5 0
2 years ago
How can I calculate the mass percent of carbon, nitrogen and oxygen in caffeine, C8H10N4O2.
Ahat [919]

You must first calculate the total weight of 1 mole of the substance. You do this by finding the molar weights on the periodic table of each of the elements in the compound:

8(12.01g)+10(1.008g)+4(14.007g)+2(15.999g)=96.08g+10.08g+56.028g+31.998g=194.186g

So now we take the amount of each element that is given in the compound and divide it by the total mass of the compound:

Carbon: 96.08g

\frac{96.08g}{194.186g}= 0.49478=49.48

Carbon = 49.48%

Nitrogen: 56.028g

\frac{56.028g}{194.186g}=0.28853=28.85

Nitrogen = 28.85%

Oxygen: 31.998g

\frac{31.998g}{194.186g} =0.16478=16.48

Oxygen = 16.48%

8 0
3 years ago
Read 2 more answers
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